Python字符串替换Dict：跳过键并离开格式化程序

我是一个字符串代替品，需要几个VAULE，我想知道是否可以跳过一个键并将其留在那里，而不填充空格

s='%(name)s has a %(animal)s that is %(animal_age)s years old'

#skip the animal value
s = s % {'name': 'Dolly', 'animal': 'bird'}#, 'animal_age': 10}

print s

预期产出：

---

您可以在字符串中使用两个

%%

，以跳过字符串格式设置：

In [169]: s='%(name)s has a %(animal)s that is %%(animal_age)s years old'

In [170]: s % {'name': 'Dolly', 'animal': 'bird', 'animal_age': 10}

Out[170]: 'Dolly has a bird that is %(animal_age)s years old'

或者使用

string.format（）

：

---

你的意思是跳过这里的

animal\u age

值吗？没错，有没有办法？

In [169]: s='%(name)s has a %(animal)s that is %%(animal_age)s years old'

In [170]: s % {'name': 'Dolly', 'animal': 'bird', 'animal_age': 10}

Out[170]: 'Dolly has a bird that is %(animal_age)s years old'

In [172]: s='{name} has a {animal} that is %(animal_age)s years old'

In [173]: dic = {'animal': 'bird', 'animal_age': 10, 'name': 'Dolly'}

In [174]: s.format(**dic)
Out[174]: 'Dolly has a bird that is %(animal_age)s years old'