Python 计算21点的数量'；100张双卡交易中出现的s

我需要数一数，从一双5层的鞋子里，100张2张牌的交易中，21点发生的次数。到目前为止，我有：

str（）-转换为字符串 convert（）-将整数（0-259；即5组）转换为卡 得分2（手牌）-计算2张牌中第二张牌的得分 我希望能够用以下方法画10只手：

hands = [draw_n(2) for i in range(100)]

---

在此之后，计算21点出现时间的最有效方法是什么？

如果没有21点，您可以使用

draw\n

返回0，如果有21点，则返回1。然后把它们加起来。

hand_total = [sum(x) for x in hands]
hand_total.count(21)

def draw_n(n):
    from random import sample
    cards = []
    # Make sure a valid number is entered
     if n >0 and n <= 260:
        # Sample without replacement
        for x in sample(xrange(0,260),n):
            # Append converted card to list 'cards'
            cards.append(convert(x))
    return cards

def score1(hand):
    if hand[0][0] == 0:
        val1 = 11
        return val1
    elif hand[0][0] == 1:
        val1 = 2
        return val1
    elif hand[0][0] == 2:
        val1 = 3
    return val1
elif hand[0][0] == 3:
    val1 = 4
    return val1
elif hand[0][0] == 4:
    val1 = 5
    return val1
elif hand[0][0] == 5:
    val1 = 6
    return val1
elif hand[0][0] == 6:
    val1 = 7
    return val1
elif hand[0][0] == 7:
    val1 = 8
    return val1
elif hand[0][0] == 8:
    val1 = 9
    return val1
elif hand[0][0] == 9 or hand[0][0] == 10 or hand[0][0] == 11 or hand[0][0] == 12:
    val1 = 10
    return val1

def score2(hand):
    if hand[1][0] == 0:
        val2 = 11
        return val2
    elif hand[1][0] == 1:
        val2 = 2
        return val2
    elif hand[1][0] == 2:
        val2 = 3
        return val2
    elif hand[1][0] == 3:
        val2 = 4
        return val2
    elif hand[1][0] == 4:
        val2 = 5
        return val2
    elif hand[1][0] == 5:
        val2 = 6
        return val2
    elif hand[1][0] == 6:
        val2 = 7
        return val2
    elif hand[1][0] == 7:
        val2 = 8
        return val2
    elif hand[1][0] == 8:
        val2 = 9
        return val2
    elif hand[1][0] == 9 or hand[1][0] == 10 or hand[1][0] == 11 or hand[1][0] == 12:
        val2 = 10
        return val2

hands = [draw_n(2) for i in range(100)]

hand_total = [sum(x) for x in hands]
hand_total.count(21)