从多个CSV列返回值到Python字典？

我试图在下面的Python字典中调用其他CSV列

该示例可以很好地返回一组值（列），但我需要为不相邻的两列返回值

import csv

# set csv file and path
allrows=list(csv.reader(open('C:/Data/Library/Peter/123.csv')))

# Extract the first row as keys for a columns dictionary
columns=dict([(x[0],x[1:]) for x in zip(*allrows)])

# Then extracting column 3 from all rows with a certain criterion in column 4
matchingrows=[rownum for (rownum,value) in enumerate(columns['Status']) if value == 'Keep']
print map(columns['book_ref'].__getitem__, matchingrows)

**sample from 123.csv**
book_id  TYPE   book_ref    Status
607842    3     9295        Keep
607844    4     7643        Keep
607846    3     2252        Retire
607856    3     7588        Keep

正确返回第3列中的值

['9644', '4406', '7643', '2252', '7588']

但是如何从第1列和第3列返回值呢

['607842':'4406', '607844':'7643', '607846':'2252', '607856':'7588']   

我也试过了，但也没能得到我想要的

##import csv
##with open('C:/Data/Library/Peter/123.csv') as f:
##    reader = csv.DictReader(f)
##    for row in reader:
##        print row
''' 
{'Status': 'Retire', 'TYPE': '3', 'book_ref': '2397', 'book_id': '607838'}
{'Status': 'Keep', 'TYPE': '12', 'book_ref': '9644', 'book_id': '607839'}
{'Status': 'Retire', 'TYPE': '4', 'book_ref': '9295', 'book_id': '607841'}
{'Status': 'Keep', 'TYPE': '3', 'book_ref': '4406', 'book_id': '607842'}
{'Status': 'Retire', 'TYPE': '4', 'book_ref': '1798', 'book_id': '607843'}
{'Status': 'Keep', 'TYPE': '4', 'book_ref': '7643', 'book_id': '607844'}
{'Status': 'Retire', 'TYPE': '3', 'book_ref': '6778', 'book_id': '607845'}
{'Status': 'Keep', 'TYPE': '3', 'book_ref': '2252', 'book_id': '607846'}
{'Status': 'Retire', 'TYPE': '4', 'book_ref': '7910', 'book_id': '607855'}
{'Status': 'Keep', 'TYPE': '3', 'book_ref': '7588', 'book_id': '607856'}

---

您可以这样简单地尝试：

with open("123.csv") as f:
    my_list = []
    next(f)
    for x in f:
        x = x.strip().split()
        my_list.append((x[0],x[2]))

---

您可以这样简单地尝试：

with open("123.csv") as f:
    my_list = []
    next(f)
    for x in f:
        x = x.strip().split()
        my_list.append((x[0],x[2]))

试试这个：

zipList = zip(*allrows[1:])
print dict(zip(zipList[0], zipList[2]))

输出：

{'607842': '9295', '607856': '7588', '607844': '7643', '607846': '2252'}

试试这个：

zipList = zip(*allrows[1:])
print dict(zip(zipList[0], zipList[2]))

输出：

{'607842': '9295', '607856': '7588', '607844': '7643', '607846': '2252'}

或者试试这个：

import csv
result={}
with open('C:/Temp/123.csv') as f:
    reader = csv.DictReader(f)
    for row in reader:
        if row['Status']=='Keep':
            result.update({row['book_id']:row['book_ref']})

这将产生：

{'607842': '9295', '607844': '7643', '607856': '7588'}

或者试试这个：

import csv
result={}
with open('C:/Temp/123.csv') as f:
    reader = csv.DictReader(f)
    for row in reader:
        if row['Status']=='Keep':
            result.update({row['book_id']:row['book_ref']})

这将产生：

{'607842': '9295', '607844': '7643', '607856': '7588'}

---

您是否尝试过csv.DictReader（[）。通过正确的映射，我认为这将解决您的问题。是的，但不是。（您的快捷方式也返回404）您是否尝试过csv.DictReader（[）。通过正确的映射，我认为这将解决您的问题。是的，但不是。（您的快捷方式也返回404）谢谢你对我有用。下面的其他回复很感谢，但不满足“状态”要求。谢谢你对我有用。下面的其他回复很感谢，但不满足“状态”要求。