Python 制作石头、布、剪刀游戏时的值错误

我刚刚开始用Python编程。我目前正在尝试建立一个石头，布，剪刀游戏。要求用户选择代表三个选项之一的数字。而pc机选择的是一个随机数。但是，我得到了一个输入行的值错误。同一行代码在不同的上下文中运行良好（无while循环），但我看不出我做错了什么。任何帮助都将不胜感激

我尝试将字符串转换为浮点，然后再转换为整数。那是行不通的。此外，我还将播放器输入数字y替换为随机数，以测试代码的其余部分。这很管用

这是我收到的错误消息：

answerplayer = int (input('What is your choice? ')) #Error
ValueError: invalid literal for int() with base 10: "runfile

守则：

import random
win = False

while win == False:
    print ('Rock, Paper, Scissors. 0: Rock; 1: Scissors; 2: Paper')
    print ('Make your choice')
    answerplayer = int (input('What is your choice? ')) #Error
    answer = random.randrange (3)
    print (answerplayer)
    print (answer)
    if answer == 0 and answerplayer == 0 :
        print ('TIE')
    elif answer == 0 and answerplayer == 1 :
        print ('PC Win')
        win = True
    elif answer == 0 and answerplayer == 2 :
        print ('Player Win')
        win = True
    elif answer == 1 and answerplayer == 0 :
        print ('Player Win')
        win = True
    elif answer == 1 and answerplayer == 1 :
        print ('TIE')
    elif answer == 1 and answerplayer == 2 :
        print ('PC Win')
        win = True
    elif answer == 2 and answerplayer == 0 :
        print ('Player Win')
        win = True
    elif answer == 2 and answerplayer == 1 :
        print ('PC Win')
        win = True
    elif answer == 2 and answerplayer == 2 :
        print ('TIE')
    else:
        print ('Player Win')
        win = True

print ('done')

---

代码很好。但是，用户输入必须是

int（）

可以转换为整数的内容

通过：

1

2

3.444

失败：

sqfe

zero

您可以通过以下方法解决：

while win == False:
    print ('Rock, Paper, Scissors. 0: Rock; 1: Scissors; 2: Paper')
    print ('Make your choice')
    answerplayer = input('What is your choice? ')
    if not answerplayer.isnumeric() :
        print ('No number')
        break
    answerplayer = int(answerplayer)
    answer = random.randrange (3)
    print (answerplayer)
    print (answer)

---

这个错误意味着当程序请求输入时，你没有给出一个有效的整数。谢谢大家，它已经被修复了。