Python从字符串调用函数

现在假设有一个名为func的函数。

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当函数名以字符串形式给出时，如何在Python 2.7中调用call func？

可以使用exec。不推荐，但可行

s = "func"

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不推荐只是演示如何执行。

您可以通过传递字符串来执行函数：

def func():
    print("hello")
s = "func"
eval(s)()

In [7]: s = "func"

In [8]: eval(s)()
hello

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最安全的方法是：

exec(s + '()')

根据上下文，您可能希望改用

globals（）

或者，您可能希望设置如下内容：

In [492]: def fun():
   .....:     print("Yep, I was called")
   .....:

In [493]: locals()['fun']()
Yep, I was called

您还可以将参数传递到函数a la中：

def spam():
    print("spam spam spam spam spam on eggs")

def voom():
    print("four million volts")

def flesh_wound():
    print("'Tis but a scratch")

functions = {'spam': spam,
             'voom': voom,
             'something completely different': flesh_wound,
             }

try:
    functions[raw_input("What function should I call?")]()
except KeyError:
    print("I'm sorry, I don't know that function")

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@巴尔加夫罗，这是一个大胆的声明@洋红新星，我很确定does@padriac，您是对的，删除注释。这不会起作用，因为您从未调用函数。是的，我知道，它只会返回函数对象，而不会调用它。我修好了。

def spam():
    print("spam spam spam spam spam on eggs")

def voom():
    print("four million volts")

def flesh_wound():
    print("'Tis but a scratch")

functions = {'spam': spam,
             'voom': voom,
             'something completely different': flesh_wound,
             }

try:
    functions[raw_input("What function should I call?")]()
except KeyError:
    print("I'm sorry, I don't know that function")

def knights_who_say(saying):
    print("We are the knights who say {}".format(saying))

functions['knights_who_say'] = knights_who_say

function = raw_input("What is your function? ")
if function == 'knights_who_say':
    saying = raw_input("What is your saying? ")
    functions[function](saying)
else:
    functions[function]()