Python 尝试解决将字符串转换为列表中的整数时出现不同错误

我有以下列表和字符串：

befcodes = ["A1","A2","A3","A4","A5","A6","A7","A8","A9","10","11","12","13","14","15","16","17","18","19","20"]
telegram = "$00;02;A1;00000000*49"

我的代码现在在字符串中更改

A1

20次，如下所示：

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes) 

result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0])[1:18]))  
print (f'{result:08b}')

for x in allbefcodes:
    allbefcodes = (int(a) for a in allbefcodes)
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18]))  # "
    print (f'{result:08b}')

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)    

for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0:])[1:18]))  # "(allbefcodes[0])" statt telegram
    print (f'{result:08b}')

allbefcodes = []
for i in befehlscodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)
   
for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in x[1:18])) 

输出以下列表：

['$00;02;A1;00000000*49', '$00;02;A2;00000000*49', '$00;02;A3;00000000*49', '$00;02;A4;00000000*49', '$00;02;A5;00000000*49', '$00;02;A6;00000000*49', '$00;02;A7;00000000*49', '$00;02;A8;00000000*49', '$00;02;A9;00000000*49', '$00;02;10;00000000*49', '$00;02;11;00000000*49', '$00;02;12;00000000*49', '$00;02;13;00000000*49', '$00;02;14;00000000*49', '$00;02;15;00000000*49', '$00;02;16;00000000*49', '$00;02;17;00000000*49', '$00;02;18;00000000*49', '$00;02;19;00000000*49', '$00;02;20;00000000*49']

现在我想使用XOR运算符来获得每个电报的二进制校验和（=每个

allbefcodes

）我这样做：

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes) 

result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0])[1:18]))  
print (f'{result:08b}')

for x in allbefcodes:
    allbefcodes = (int(a) for a in allbefcodes)
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18]))  # "
    print (f'{result:08b}')

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)    

for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0:])[1:18]))  # "(allbefcodes[0])" statt telegram
    print (f'{result:08b}')

allbefcodes = []
for i in befehlscodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)
   
for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in x[1:18])) 

对于

allbefcodes[0]

，这确实很好，我得到了输出

01001001

。但是我现在想用循环为所有

allbefcodes

的字符执行此操作，在循环中我会得到不同的错误。以下是我迄今为止尝试的：

for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18]))  
    print (f'{result:08b}')

错误

TypeError：列表索引必须是整数或片，而不是str

。我试着这样解决它：

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes) 

result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0])[1:18]))  
print (f'{result:08b}')

for x in allbefcodes:
    allbefcodes = (int(a) for a in allbefcodes)
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18]))  # "
    print (f'{result:08b}')

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)    

for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0:])[1:18]))  # "(allbefcodes[0])" statt telegram
    print (f'{result:08b}')

allbefcodes = []
for i in befehlscodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)
   
for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in x[1:18])) 

但是这里出现了错误

TypeError:“generator”对象不可下标。所以我下一步尝试了这个：

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
allbefcodes = (int(a) for a in allbefcodes)     #Tried to solve it with this line
print (allbefcodes)    

for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18]))  # "(allbefcodes[0])" statt telegram
    print (f'{result:08b}')

但是现在错误
ValueError:int（）的文本无效，以10为底：'$00；02;A1；00000000*49'
发生。对allbefcodes中的a执行
（float（int（a））
不会改变这一点。
我最后一次尝试是将
（allbefcodes[x]）
更改为
（allbefcodes[0:]）
，并将
allbefcodes=（int（a）表示a in-allbefcodes）
保留为out，如下所示：

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes) 

result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0])[1:18]))  
print (f'{result:08b}')

for x in allbefcodes:
    allbefcodes = (int(a) for a in allbefcodes)
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18]))  # "
    print (f'{result:08b}')

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)    

for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0:])[1:18]))  # "(allbefcodes[0])" statt telegram
    print (f'{result:08b}')

allbefcodes = []
for i in befehlscodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)
   
for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in x[1:18])) 

但是现在我得到了
TypeError:ord（）应该是一个字符，但是找到了长度为21的字符串
，这让我再次需要整数而不是字符串，我已经试着解决了……我真的不知道该怎么做了，非常感谢您的帮助
 我想出来了！
我只需将
（allbefcodes[0:]）
替换为
x
，如下所示：

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes) 

result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0])[1:18]))  
print (f'{result:08b}')

for x in allbefcodes:
    allbefcodes = (int(a) for a in allbefcodes)
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[x])[1:18]))  # "
    print (f'{result:08b}')

allbefcodes = []
for i in befcodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)    

for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in (allbefcodes[0:])[1:18]))  # "(allbefcodes[0])" statt telegram
    print (f'{result:08b}')

allbefcodes = []
for i in befehlscodes:
    dif_tele = telegram.replace("A1", i)
    allbefcodes.append(dif_tele)
print (allbefcodes)
   
for x in allbefcodes:
    result = functools.reduce(operator.xor,(ord(n) for n in x[1:18])) 

您发现的错误
TypeError:“generator”对象不可下标
，是因为您使用了由parantesses分隔的理解，从而创建了生成器。带有
TypeError:ord（）的最后一行应为字符，但找到了长度为21的字符串
，因为您正在迭代一个列表，其中每个条目都是
allbefcodes
中的一个元素，该列表是长度为21的
字符串。