Python 如何将2个列表配对为1个列表

我有这样一个代码：

def datauji(self):
    uji = []
    for x in self.fiturs:
        a = [x[0],x[-5:]] #I think the problem in this line
        uji.append(a)
    return uji

with open('DataUjiBaru.csv','wb') as dub:
        testing = csv.writer(dub)
        datatest = d.datauji()
        datatest.pop(0)
        for x in datatest:
            testing.writerow(x)

F37,"['1', '0', '0', '0', '1']"
F10,"['8', '4', '5', '6', '4']"
F8,"['0', '0', '2', '0', '0']"

F37,1,0,0,0,1
F10,8,4,5,6,4
F8,0,0,2,0,0

['F37', ['1', '0', '0', '0', '1']]

我想将self.fiturs中的值与self.fiturs中的值配对：

F37,0,1,0,1,1,1,0,1,0,2,1,0,0,0,1
F10,8,4,3,3,3,6,8,5,8,4,8,4,5,6,4
F8,1,0,2,0,0,0,2,0,0,0,0,0,2,0,0

所以我想将索引[0]和索引[-5:]配对，并将其写入csv，csv上的输出如下：

def datauji(self):
    uji = []
    for x in self.fiturs:
        a = [x[0],x[-5:]] #I think the problem in this line
        uji.append(a)
    return uji

with open('DataUjiBaru.csv','wb') as dub:
        testing = csv.writer(dub)
        datatest = d.datauji()
        datatest.pop(0)
        for x in datatest:
            testing.writerow(x)

F37,"['1', '0', '0', '0', '1']"
F10,"['8', '4', '5', '6', '4']"
F8,"['0', '0', '2', '0', '0']"

F37,1,0,0,0,1
F10,8,4,5,6,4
F8,0,0,2,0,0

['F37', ['1', '0', '0', '0', '1']]

我对csv的期望如下：

def datauji(self):
    uji = []
    for x in self.fiturs:
        a = [x[0],x[-5:]] #I think the problem in this line
        uji.append(a)
    return uji

with open('DataUjiBaru.csv','wb') as dub:
        testing = csv.writer(dub)
        datatest = d.datauji()
        datatest.pop(0)
        for x in datatest:
            testing.writerow(x)

F37,"['1', '0', '0', '0', '1']"
F10,"['8', '4', '5', '6', '4']"
F8,"['0', '0', '2', '0', '0']"

F37,1,0,0,0,1
F10,8,4,5,6,4
F8,0,0,2,0,0

['F37', ['1', '0', '0', '0', '1']]

---

如何解决此问题？

您的代码问题是正确的，可以在以下行中找到：

a = [x[0],x[-5:]]

这将创建如下所示的嵌套项：

def datauji(self):
    uji = []
    for x in self.fiturs:
        a = [x[0],x[-5:]] #I think the problem in this line
        uji.append(a)
    return uji

with open('DataUjiBaru.csv','wb') as dub:
        testing = csv.writer(dub)
        datatest = d.datauji()
        datatest.pop(0)
        for x in datatest:
            testing.writerow(x)

F37,"['1', '0', '0', '0', '1']"
F10,"['8', '4', '5', '6', '4']"
F8,"['0', '0', '2', '0', '0']"

F37,1,0,0,0,1
F10,8,4,5,6,4
F8,0,0,2,0,0

['F37', ['1', '0', '0', '0', '1']]

有两种方法可以解决此问题：

选项1-使用splat*运算符：

a = [x[0],*x[-5:]]

选项2-连接列表的两个部分：

a = x[:1] + x[-5:]

这两种方法都将删除列表的嵌套，并为您提供如下所示的行：

['F37', '1', '0', '0', '0', '1']

---

然后可以将其写入输出文件。

非常感谢@chrisz