Python 如果我没有'；你不能动我的鼠标吗？

我已经设法通过线程执行了这个函数，但是过了一会儿它就停止工作了，直到我再次移动鼠标，如果我最小化窗口，线程就会停止，直到我重新打开窗口

import tkinter as tk,tkinter.ttk as ttk, pyautogui, numpy as np, easygui, cv2, os, sys, re, math, subprocess, threading, requests, PIL.Image, random, time

函数我正在尝试运行线程

 def runScript(self):
        def on_release(key):
            if key == keyboard.Key.esc:
                print('test')
                return False
        listener = keyboard.Listener(
            on_release=on_release)
        listener.start()
        
##        self.toplevel1.iconify()
        e1 = lb_0.get()
        if loopVar.get() == True:  
                if moveVar.get() == True and randVar.get() == True:
                        while loopVar.get() == True:
                            for i in range(len(e1)):
                                e1, e2, e3, e4 = lb_0.get(), lb_1.get(), lb_2.get(), lb_3.get()
                                xyCoor1 = [int(s) for s in re.findall(r'\b\d+\b', str(e1[i]))]
                                xyCoor2 = [int(s) for s in re.findall(r'\b\d+\b', str(e2[i]))]
                                cCoor1 = [int(s) for s in re.findall(r'\b\d+\b', str(e3[i]))]
                                iCoor1 = [int(s) for s in re.findall(r'\b\d+\b', str(e4[i]))]
                                randLoc = int(randText.get().strip())
                                randX1 = int(xyCoor1[0] - int(randLoc) / 2)
                                print('w')
                                randX2 = int(xyCoor1[0] + int(randLoc) / 2)
                                randY1 = int(xyCoor2[0] - int(randLoc) / 2)
                                randY2 = int(xyCoor2[0] + int(randLoc) / 2)
                                trueX = int(random.randint(randX1,randX2))
                                trueY = int(random.randint(randY1,randY2))
                                print(trueX)
                                print(trueY)
                                pyautogui.PAUSE = iCoor1[0]
                                pyautogui.moveTo(x=trueX, y=trueY, duration=0.05, _pause=False)
                                pyautogui.click(x=trueX, y=trueY, clicks=cCoor1[0], button='left')

    def threadRunScript(self, event):
        t = threading.Thread(target=self.runScript)
        t.daemon = True
        t.start()
    pass

创建线程的函数

 def runScript(self):
        def on_release(key):
            if key == keyboard.Key.esc:
                print('test')
                return False
        listener = keyboard.Listener(
            on_release=on_release)
        listener.start()
        
##        self.toplevel1.iconify()
        e1 = lb_0.get()
        if loopVar.get() == True:  
                if moveVar.get() == True and randVar.get() == True:
                        while loopVar.get() == True:
                            for i in range(len(e1)):
                                e1, e2, e3, e4 = lb_0.get(), lb_1.get(), lb_2.get(), lb_3.get()
                                xyCoor1 = [int(s) for s in re.findall(r'\b\d+\b', str(e1[i]))]
                                xyCoor2 = [int(s) for s in re.findall(r'\b\d+\b', str(e2[i]))]
                                cCoor1 = [int(s) for s in re.findall(r'\b\d+\b', str(e3[i]))]
                                iCoor1 = [int(s) for s in re.findall(r'\b\d+\b', str(e4[i]))]
                                randLoc = int(randText.get().strip())
                                randX1 = int(xyCoor1[0] - int(randLoc) / 2)
                                print('w')
                                randX2 = int(xyCoor1[0] + int(randLoc) / 2)
                                randY1 = int(xyCoor2[0] - int(randLoc) / 2)
                                randY2 = int(xyCoor2[0] + int(randLoc) / 2)
                                trueX = int(random.randint(randX1,randX2))
                                trueY = int(random.randint(randY1,randY2))
                                print(trueX)
                                print(trueY)
                                pyautogui.PAUSE = iCoor1[0]
                                pyautogui.moveTo(x=trueX, y=trueY, duration=0.05, _pause=False)
                                pyautogui.click(x=trueX, y=trueY, clicks=cCoor1[0], button='left')

    def threadRunScript(self, event):
        t = threading.Thread(target=self.runScript)
        t.daemon = True
        t.start()
    pass

指向功能的按钮

        #Run script button
        self.button3 = tk.Button(self.labelframe1)
        self.button3.configure(activeforeground='#000000', font='{Century Gothic} 13 {}', foreground='#fefffe', highlightbackground='#393a4c')
        self.button3.configure(highlightcolor='#2e2a2e', highlightthickness='100', justify='center', relief='raised', command=self.threadRunScript)
        self.button3.configure(image=imgToButton4("/Users/giuseppemarziano/Desktop/Scripts/Personal Projects/Auto Click GM/ACGM 0.04/ACGM Images/start.svg"))
        self.button3.place(anchor='nw', height='25', relx='0.0', rely='0.0', width='25', x='320', y='4')
        self.button3.bind('<1>', self.threadRunScript, add='+')

主回路

if __name__ == '__main__':
    app = Acgm003App()
    app.run()

我曾尝试使用

queue.queue

，但它不允许我在不传递参数的情况下使用，我也尝试过类似于

self.toplevel1.after（1000，self.update（））

，但它无法正常工作

---

有没有一种简单的方法可以让函数继续运行，或者以给定的时间间隔刷新gui以允许线程不被中断？

因此我通过在主类中添加以下内容来修复它：

self.mainwindow.after(10, self.updateMy)

    def updateMy(self):
        self.mainwindow.after(10, self.updateMy)
    pass

上面的代码将每隔10毫秒创建一个循环，以便

根目录更新自身

我不确定这是否会导致资源方面的复杂性。
没有完全阅读，但这是正确的方法（在大多数情况下）：
self.toplevel1.after（1000，self.update）
@Matiss，我应该把它放在哪里？在我构建对象的主函数中，或者在我想要线程的函数中？
tkinter
是单线程的，不建议在其上使用线程。@CoolCloud，阻止窗口冻结的最佳方法是什么？使用另一个线程：pGlad您找到了解决方案：D