无法选择LinkedIn'；地点'；使用Python Selenium的按钮

我正试图点击LinkedIn中的位置下拉列表。通过在LinkedIn搜索栏中搜索某些内容，然后单击“人员”，您将进入LinkedIn页面的这一部分

这是HTML元素：

<button aria-checked="false" role="button" aria-label="Locations filter. Clicking this button displays all Locations filter options." 
id="ember745" class="artdeco-pill artdeco-pill--slate artdeco-pill--2 artdeco-pill--choice ember-view search-reusables__filter-pill-button" aria-controls="artdeco-hoverable-artdeco-gen-54" aria-expanded="false" data-control-name="filter_top_bar_select" type="button">  
      Locations
<!---->      <li-icon aria-hidden="true" type="caret-filled-down-icon" class="search-reusables__pill-button-caret-icon" size="small"><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 16 16" data-supported-dps="16x16" fill="currentColor" class="mercado-match" width="16" height="16" focusable="false">
  <path d="M8 11L3 6h10z" fill-rule="evenodd"></path>
</svg></li-icon>
    
</button>

我在这方面花了很多时间，但还没有找到解决方案

点击位置后，我还想选择美国，然后点击公司名称并写下公司名称

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下一部分： 这是“美国”位置的html。我想点击“美国”并搜索该过滤器

<li class="search-reusables__collection-values-item">
        <input aria-label="Filter by United States" name="United States" id="geoUrn-103644278" class="search-reusables__select-input" data-control-name="filter_detail_select" type="checkbox" value="103644278">
        <label for="geoUrn-103644278" class="search-reusables__value-label">
          <p class="display-flex">
            <span class="t-14 t-black--light t-normal">
              United States
            </span>
          </p>
        </label>
<!---->      </li>

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可以使用此XPath找到该特定按钮：

//span//button[contains(@aria-label,'Locations filter')]

因此，可以通过

locations_btn = WebDriverWait(browser, 10).until(EC.visibility_of_element_located((By.XPATH, '//span//button[contains(@aria-label,"Locations filter")]')))

“美国”位置可由以下人员选择：

WebDriverWait(browser, 10).until(EC.visibility_of_element_located((By.XPATH, '//div[contains(@id,"locations-filter")]//li[@class="search-reusables__collection-values-item"]//span[contains(.,"United States")]'))).click()

或者，如果要单击该复选框，可以使用以下内容：

WebDriverWait(browser, 10).until(EC.visibility_of_element_located((By.XPATH, '//div[contains(@id,"locations-filter")]//li[@class="search-reusables__collection-values-item" and .//span[contains(.,"United States")]]//input'))).click()

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谢谢@Prophet。你能写出代码的全部语句吗？你是什么意思？我的意思是为上面的语句编写完整的代码，比如：browser.find_element_by_xpath…etcis这就是你想要的？更新的答案谢谢！你能再帮我一件事吗。我想选择美国作为一个地点。我应该如何选择它？我将粘贴问题中的html。

WebDriverWait(browser, 10).until(EC.visibility_of_element_located((By.XPATH, '//div[contains(@id,"locations-filter")]//li[@class="search-reusables__collection-values-item"]//span[contains(.,"United States")]'))).click()

WebDriverWait(browser, 10).until(EC.visibility_of_element_located((By.XPATH, '//div[contains(@id,"locations-filter")]//li[@class="search-reusables__collection-values-item" and .//span[contains(.,"United States")]]//input'))).click()