Python $ne不'；我不能和pymongo一起工作

my

$ne:“

与pymongo一起工作不正常

hashtable['ACR-WEB-01']=db.logs.find({"host_name" : "WEB-01"}, {"service_description": {"$ne" : ""}}).distinct("service_description")
print hashtable['ACR-WEB-01']

打印的结果是：

[u'Disks', u'', u'Mem', u'VM Tools', u'Cpu', u'vm-alarm-CPU', u'vm-alarm-MEM', u'vm-alarm-VMTOOLS', u'Uptime']

正如你所看到的，我得到了

u'

为什么

如果我直接在mongodb中执行此操作，它会起作用：

> db.logs.distinct( "service_description" , { "host_name" : "WEB-01", service_description: {$ne : ""}} )
[
    "Cpu",
    "Disks",
    "Mem",
    "Uptime",
    "VM Tools",
    "vm-alarm-CPU",
    "vm-alarm-MEM",
    "vm-alarm-VMTOOLS"
]

---

感谢您的帮助

您需要将两个

查找

查询词放在同一个哈希对象中：

hashtable['ACR-WEB-01']=db.logs
    .find({"host_name": "WEB-01", "service_description": {"$ne" : ""}})
    .distinct("service_description")