Python 当我尝试运行django development server（使用命令行）时，我得到以下错误回溯：

我的系统是：Ubuntu16.04。 Python版本：3.5.2 Django版本：2.0.2

root@nanlyvm:/home/mydj/mysite# python manage.py runserver
Performing system checks...

Unhandled exception in thread started by <function check_errors.<locals>.wrapper at 0x7fbb791cd1e0>
Traceback (most recent call last):
  File "/usr/local/lib/python3.5/dist-packages/django/utils/autoreload.py", line 225, in wrapper
    fn(*args, **kwargs)
  File "/usr/local/lib/python3.5/dist-packages/django/core/management/commands/runserver.py", line 121, in inner_run
    self.check(display_num_errors=True)
  File "/usr/local/lib/python3.5/dist-packages/django/core/management/base.py", line 364, in check
    include_deployment_checks=include_deployment_checks,
  File "/usr/local/lib/python3.5/dist-packages/django/core/management/base.py", line 351, in _run_checks
    return checks.run_checks(**kwargs)
  File "/usr/local/lib/python3.5/dist-packages/django/core/checks/registry.py", line 73, in run_checks
    new_errors = check(app_configs=app_configs)
  File "/usr/local/lib/python3.5/dist-packages/django/core/checks/urls.py", line 40, in check_url_namespaces_unique
    all_namespaces = _load_all_namespaces(resolver)
  File "/usr/local/lib/python3.5/dist-packages/django/core/checks/urls.py", line 57, in _load_all_namespaces
    url_patterns = getattr(resolver, 'url_patterns', [])
  File "/usr/local/lib/python3.5/dist-packages/django/utils/functional.py", line 36, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "/usr/local/lib/python3.5/dist-packages/django/urls/resolvers.py", line 536, in url_patterns
    patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
  File "/usr/local/lib/python3.5/dist-packages/django/utils/functional.py", line 36, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "/usr/local/lib/python3.5/dist-packages/django/urls/resolvers.py", line 529, in urlconf_module
    return import_module(self.urlconf_name)
  File "/usr/lib/python3.5/importlib/__init__.py", line 126, in import_module
    return _bootstrap._gcd_import(name[level:], package, level)
  File "<frozen importlib._bootstrap>", line 986, in _gcd_import
  File "<frozen importlib._bootstrap>", line 969, in _find_and_load
  File "<frozen importlib._bootstrap>", line 958, in _find_and_load_unlocked
  File "<frozen importlib._bootstrap>", line 673, in _load_unlocked
  File "<frozen importlib._bootstrap_external>", line 665, in exec_module
  File "<frozen importlib._bootstrap>", line 222, in _call_with_frames_removed
  File "/home/mydj/mysite/mysite/urls.py", line 22, in <module>
    url(r'^blog/',include('blog.urls', namespace='blog', app_name='blog')),
TypeError: include() got an unexpected keyword argument 'app_name'

这是我的URL.py，↓我将其存储在/home/mydj/mysite/mysite中

from django.conf.urls import url, include
from django.contrib import admin

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^blog/',include('blog.urls', namespace='blog', app_name='blog')),
]

---

您必须更改URL模式

from django.conf.urls import url, include
from django.contrib import admin

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^blog/',include('blog.urls', name='blog')),
]

---

参考：

这在Django 1.9中被弃用，在2.0中被删除

现在可以使用包含的模块或对象上的app_name属性设置应用程序名称空间。也可以通过传递2元组（，）作为包含（）的第一个参数来设置它

---

新版本包括：

根据新版本，请尝试：

from django.urls import include, path

urlpatterns = [
    path('index/', views.index, name='main-view'),
    path('blog', views.blog, name='blog'),
    ...
]

---

来源：

我根据你的意见修改了它，但它仍然犯了同样的错误。在我更改了我使用的Django版本之后。它可以正确使用。非常感谢。我根据你的意见修改了它，但仍然犯了同样的错误。在我更改了我使用的Django版本之后。它可以正确使用。非常感谢。谢谢你的评论，似乎不是因为这个原因。在我更改了我使用的Django版本之后。它可以正确使用。非常感谢。今天是个好天气。在我更改了我使用的Django版本之后。它可以正确使用。谢谢所有帮助我的人。

from django.urls import include, path

urlpatterns = [
    path('index/', views.index, name='main-view'),
    path('blog', views.blog, name='blog'),
    ...
]