在python中尝试减去两个日期并以小时（大于24小时的时间段）为单位获得结果

在python中尝试减去两个日期并以小时（大于24小时的时间段）为单位获得结果

这就是我尝试过的：

    currentdate = datetime.now()
    # gets the date from the website
    lastcrawl = driver.find_element_by_xpath('//*[@id="last-15336"]/h4').text
    # convert string into time format
    formatlastcrawl = datetime.strptime(lastcrawl, '%b %d %H:%M')
    # converts into the time format - April 28, 11:24
    newformatlastcrawl = formatlastcrawl.strftime('%b %d %H:%M')
    print newformatlastcrawl
    # substracts 24 hours of the current date(because the website crawl happens every 24 hours) + 2 hours(to give enough time to finish the crawl)
    substractdate = (currentdate - timedelta(hours=26)).strftime("%b %d %H:%M")
    print substractdate
    # changes the format of the current date. For example - Nov 12
    formatcurrentdate = currentdate.strftime("%b %d %H:%M")
    print formatcurrentdate

    a = (substractdate - newformatlastcrawl)
    print a

当我尝试减去它时，我会得到以下错误：

a=（substractdate-newformatlastcrawl）.strTime（“%b%d%H:%M”） TypeError:-：“str”和“str”的操作数类型不受支持

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我只想在几个小时内得到答案。此外，时间值可以大于24小时

此程序以小时为单位打印两次之间的差值

from datetime import datetime

now = datetime.now()

# Problem: no year specified!
b = datetime.strptime('Apr 24 11:24', '%b %d %H:%M')

# Fix: Use the current year
b = b.replace(year=now.year)

# Goal: print number of hours between the two dates
diff_in_hours = (now - b).total_seconds() / 3600
print '{} - {} = {} hours'.format(now, b, diff_in_hours)

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与标题相关：如果utc偏移量不固定（例如，如果本地时区遵守DST），则使用原始的datetime对象，如

datetime.now（）返回的datetime对象可能会导致错误的时差。