Python 写入CSV文件时未筛选行
此代码用于查找特定时间范围内(在本例中为2018年)的延迟交付,并将数据写入csv文件(otdedit.csv)。但是,尽管数据按年份正确过滤,但未延迟交付的值不会被过滤掉。我的问题是,如何筛选出只有延迟交付的行,将其写入csv文件otdedit.csvPython 写入CSV文件时未筛选行,python,pandas,csv,datetime,export-to-csv,Python,Pandas,Csv,Datetime,Export To Csv,此代码用于查找特定时间范围内(在本例中为2018年)的延迟交付,并将数据写入csv文件(otdedit.csv)。但是,尽管数据按年份正确过滤,但未延迟交付的值不会被过滤掉。我的问题是,如何筛选出只有延迟交付的行,将其写入csv文件otdedit.csv import pandas as pd from datetime import datetime from datetime import timedelta PURCHASE_ORDER = 'Material' DELIVERY_DA
import pandas as pd
from datetime import datetime
from datetime import timedelta
PURCHASE_ORDER = 'Material'
DELIVERY_DATE = 'Delivery Date'
DESIRED_DATE = 'Desired Delivery'
DELAYED_DAYS = 'Delayed Days'
df = pd.read_csv('otd.csv', index_col=PURCHASE_ORDER)
df[DELIVERY_DATE] = pd.to_datetime(df[DELIVERY_DATE])
df[DESIRED_DATE] = pd.to_datetime(df[DESIRED_DATE])
df[DELAYED_DAYS] = df[DELIVERY_DATE] - df[DESIRED_DATE]
late_threshold = pd.Timedelta(days=0)
late_deliveries = df[DELAYED_DAYS] > late_threshold
df[late_deliveries].drop([DELIVERY_DATE, DESIRED_DATE], axis=1)
df['Delivery Date'] = pd.to_datetime(df['Delivery Date'], format='%m/%d/%Y')
df['Desired Delivery'] = pd.to_datetime(df['Desired Delivery'], format='%m/%d/%Y')
df2 = df[(df['Delivery Date'].dt.year >= 2018) & (df['Delivery Date'].dt.year <= 2018)]
df2['Diff Deliv Date'] = df2['Delivery Date'] - df2['Desired Delivery']
df2.to_csv('otdedit.csv', sep=',')
线路
df[late_deliveries].drop([DELIVERY_DATE, DESIRED_DATE], axis=1)
正在将视图的副本创建到原始数据框中,并删除给定的列,但是您没有将此副本分配给任何对象。原始数据帧df
不变
创建df2后,您可以做的是:
df2 = df2[df2[DELAYED_DAYS] > late_threshold]
df2.drop([DELIVERY_DATE, DESIRED_DATE], axis=1, inplace=True)
线路
df[late_deliveries].drop([DELIVERY_DATE, DESIRED_DATE], axis=1)
正在将视图的副本创建到原始数据框中,并删除给定的列,但是您没有将此副本分配给任何对象。原始数据帧df
不变
创建df2后,您可以做的是:
df2 = df2[df2[DELAYED_DAYS] > late_threshold]
df2.drop([DELIVERY_DATE, DESIRED_DATE], axis=1, inplace=True)
嘿,你能把示例数据作为csv或使用
df2.to_dict()
的输出给我们吗?嘿,你能把示例数据作为csv或使用df2.to_dict()
的输出给我们吗?