当我试图使用python函数时，我很困惑它们是如何工作的

所以代码是

magician_names = ['Elon musk', 'Neuralink', 'Neuralink']

def show_magicians(names):
    print("each object/person in the list:\n")
    for name in names:
        print(name.title())

def make_great(list):
    for q in list:
        q = 'the Great ' + q.title()


make_great(magician_names)
print(magician_names)

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您只是重新分配循环变量

q

，而不是实际改变列表：

def make_great(list):
    for q in list:
        q = 'the Great ' + q.title()  
        # q is now a different new str object, but list is unchanged

改为：

def make_great(lst):  # also do not shadow the built-in list
    for i in range(len(lst)):
        lst[i] = 'the Great ' + lst[i].title()

---

上面的答案也是正确的，你们并没有改变清单，我会尽力澄清一些事情 让我们看看发生了什么，看看评论

magician_names = ['Elon musk', 'Neuralink', 'Neuralink'] #declared a list

def show_magicians(names): #defined a function though never called
    print("each object/person in the list:\n")
    for name in names:
        print(name.title())

def make_great(list): # defined a function
    for q in list: #iterated on list
        q = 'the Great ' + q.title() # stored a result into memory never used or printed it or returned anything


make_great(magician_names) #called the function operated on list never printed it but it worked in memory
print(magician_names)

简单地说，如果你的房间里有狗Maxi（假设有一个函数），除非你打电话给它，否则它不会来找你。但马克西将留在这里表演魔术师。你打电话给Maxi，让他安静地说woof woof，这样你就再也听不到他的声音了，但是Maxi说了，做了他的工作（这里没有打印声明）

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试着在现实世界中进行类比，希望能有所帮助

你对哪一部分有困难？问题是什么？当我打印（魔术师的名字）时，我应该得到列表中每个项目之间的伟大的输出