Python 将数据帧拆分为多个重叠行

需要将其拆分为多个数据帧的数据帧。每6行（自上而下）成为一个新的数据帧

下面的行可以很好地工作，如屏幕截图

import pandas as pd

data = {'ID': ["a1","a2","a3","a4","a5","a6","a7","a8","a9","a10","a11","a12","a13","a14","a15","a16","a17","a18","a19","a20","a21","a22"], 
'Unit_Weight': [178,153,193,195,214,157,205,212,219,166,217,186,170,207,204,201,179,215,213,170,217,199]}

df = pd.DataFrame(data)

size = 6      # 6 rows in a new data-frame
list_of_dfs = [df.loc[i:i+size-1,:] for i in range(0, len(df),size)]

for l_d in list_of_dfs:
    print l_d

现在我想从下到上做，因为df_2，它包括上一个数据帧的最后两行

用Python实现这一点的正确方法是什么？多谢各位

这对我很有效：-

import pandas as pd

data = {'ID': ["a1","a2","a3","a4","a5","a6","a7","a8","a9","a10","a11","a12","a13","a14","a15","a16","a17","a18","a19","a20","a21","a22"], 
'Unit_Weight': [178,153,193,195,214,157,205,212,219,166,217,186,170,207,204,201,179,215,213,170,217,199]}

df = pd.DataFrame(data)


size = 6      # 6 rows in a new data-frame
list_of_dfs = [df.loc[i:i+size-1,:] for i in range(0, len(df),size-2) if i <len(df)-2]

for l_d in list_of_dfs:
    print (l_d)

将熊猫作为pd导入
数据={'ID'：[“a1”，“a2”，“a3”，“a4”，“a5”，“a6”，“a7”，“a8”，“a9”，“a10”，“a11”，“a12”，“a13”，“a14”，“a15”，“a16”，“a17”，“a18”，“a19”，“a20”，“a21”，“a22”]，
‘单位重量’：[17815319319521415720521221916621718617020720420401792115213170217199]}
df=pd.DataFrame（数据）
大小=新数据帧中的6#6行
如果i我将向前工作，但只是向后计数数据帧编号，则在范围（0，len（df），size-2）内的i的列表_of_dfs=[df.loc[i:i+size-1，：]

df_num = 5
li_dicts = {}

for x in range(0,17,4):
    y = x + 6
    df_temp = df.iloc[x:y,:]
    li_dicts[("df_" + str(df_num))] = df_temp
    df_num -= 1

li_dicts['df_5']

   ID  Unit_Weight
0  a1          178
1  a2          153
2  a3          193
3  a4          195
4  a5          214
5  a6          157

我更喜欢@Udit Hari Vashisht回答！