Python 两个长度不等的数据帧的交集

如果有行匹配，我试图获得“游戏”和“示例”数据帧之间的交集。数据帧的大小不等，我不希望一行在相交时计数两次

例如， 示例数据帧有行

[0,1,1]，[1,1,0]，[1,0,1]，[0,1,1]

游戏数据帧有行

[1,1,0]，[1,1,0]，[1,0,1]，[1,1,1]，[1,0,1]

现在，交叉点数据帧应该有行

[1,1,0]，[1,0,1]

import pandas as pd
import numpy as np
import random
trials = 1000
games = 3
data = pd.DataFrame()         
for i in range(trials):
    for j in range(games):
        data.loc[i,j] = random.choice([0,1])

sample = pd.DataFrame()
for i in range(trials):
    for j in range(games):
        if ((data.loc[i,:]).sum()) >= 2:
            sample.loc[i,j] = data.loc[i,j]

game = pd.DataFrame()
for i in range(trials):
    for j in range(games):
        if (data.loc[i,0]) == 1:
            game.loc[i,j] = data.loc[i,j]

intersection = pd.DataFrame()
for i in range(len(sample)):
    if np.all(sample.iloc[i,:] == game.iloc[i,:]):
        for j in range(games):
            intersection.loc[i,j] = sample.loc[i,j]

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您可以尝试使用条件检查第二个数据帧中的类似行

df1 = pd.DataFrame([[0,1,1],[1,1,0],[1,0,1],[0,1,1]])
df2 = pd.DataFrame([[1,1,0],[1,1,0],[1,0,1],[1,1,1],[1,0,1]])

df1[df1.isin(df2).all(1)]

输出：

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这回答了你的问题吗？

    0   1   2
1   1   1   0
2   1   0   1