Python 如何删除重复值？例如，如果我有5+10=15，那么我不想打印10+5=15

我得到了输出：

arr1    =    [x for x in range (1,100) if all(x%y!=0 for y in range (2,x))]
arr2    =    arr1
arr3    =    [x for x in range (1,100) if x%2==0]
for i in arr3:
    for j in arr1:
        for k in arr2:
            if (j+k==i) and (j!=k):
                print (j,"+",k,"=",i)

但我不想要下面的部分，因为这只是重复j和 k位置更改。只需打印前7个

11 + 73 = 84
13 + 71 = 84
17 + 67 = 84
23 + 61 = 84
31 + 53 = 84
37 + 47 = 84
41 + 43 = 84
43 + 41 = 84
47 + 37 = 84
53 + 31 = 84
61 + 23 = 84
67 + 17 = 84
71 + 13 = 84
73 + 11 = 84

对于所有其他偶数也是如此。 哥德巴赫猜想——每个偶数都可以表示为两个数的和

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素数。在那里，

可能会将结果存储在一个列表中，并检查它是否已经打印出来

43 + 41 = 84
47 + 37 = 84
53 + 31 = 84
61 + 23 = 84
67 + 17 = 84
71 + 13 = 84
73 + 11 = 84

而不是arr2=arr1

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应该做到这一点，一个简单的改变可能是：

arr2 = arr1[:len(arr1) // 2)]

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您可以使用另一个子句，即j将元组k，j中j，k的倒序添加到一个集合中，然后在打印之前检查j，k是否不在下一次出现的集合中。TypeError：切片索引必须是整数或无，或者具有_索引_u方法

arr2 = arr1[:len(arr1) // 2)]

arr1    =    [x for x in range (1,100) if all(x%y!=0 for y in range (2,x))]
arr2    =    arr1
arr3    =    [x for x in range (1,100) if x%2==0]
for i in arr3:
    for j in arr1:
        for k in arr2:
            if (j+k==i) and (j<k): # change made here
                print (j,"+",k,"=",i)

arr1    =    [x for x in range (1,100) if all(x%y!=0 for y in range (2,x))]
arr3    =    [x for x in range (1,100) if x%2==0]
for i in arr3:
    for j in arr1:
        for k in arr1: # looking in the same array as j
            if (j+k==i) and (j<k):
                print (j,"+",k,"=",i)