Python Tkinter仅适用于一次按钮按下，而不适用于其他按钮按下？

我使用Tkinter窗口通过串行端口将信息传递给arduino，arduino将步进电机转动一定的步数。基本上，我有按钮，对应的步骤，我希望电机采取的数量。当我按下按钮时，我想让马达移动那么多步。我会发布一些我的代码片段，但基本上我的问题是，第一次按下按钮时窗口工作得很好，但当我点击其他按钮让电机继续运转时，我什么也看不到。Tkinter窗口似乎只适用于一次单击，或者卡在回调函数或其他什么东西中

回调函数：

def firstGrating():
    arduino.write('1800')
    tkMessageBox.showwarning(title= 'Spectrometer', message = 'I am moving to the 1800 Grating...')
    tkMessageBox.showwarning(title= 'Spectrometer', message = 'Please Wait Until I Tell You That I AM FINISHED!!!')
    while True:
        message = arduino.readline()
        if len(message) > 10:
            tkMessageBox.showwarning(title= 'Spectrometer', message = message)
    return

def secondGrating():
    arduino.write('150')
    tkMessageBox.showwarning(title= 'Spectrometer', message = 'I am moving to the 150 Grating...')
    tkMessageBox.showwarning(title= 'Spectrometer', message = 'Please Wait Until I Tell You That I AM FINISHED!!!')
    while True:
        message = arduino.readline()
        if len(message) > 10:
            tkMessageBox.showwarning(title= 'Spectrometer', message = message)
    return

def thirdGrating():
    arduino.write('3600')
    tkMessageBox.showwarning(title= 'Spectrometer', message = 'I am moving to the 3600 Grating...')
    tkMessageBox.showwarning(title= 'Spectrometer', message = 'Please Wait Until I Tell You That I AM FINISHED!!!')
    while True:
        message = arduino.readline()
        if len(message) > 10:
            tkMessageBox.showwarning(title= 'Spectrometer', message = message)
    return

这是我尝试设置Tkinter窗口的部分：

win = Tk()
win.geometry("600x400+500+500")
win.title('Spectrometer Controller')

mlabel = Label(text = 'Select One of The Available Gratings')
mlabel.pack()

mButton1 = Button(win, text = '1800', command = lambda: firstGrating())
mButton1.pack()#.grid(row=0, column=1)
mButton2 = Button(win, text = '150', command = lambda: secondGrating())
mButton2.pack()#.grid(row=0, column=2)
mButton3 = Button(win, text = '3600', command = lambda: thirdGrating())
mButton3.pack()#.grid(row=0, column=3)

win.mainloop()

---

你说得对，电话卡在回拨电话里了

Tkinter

的

mainloop（）

与

while

循环产生冲突并变得无响应，因此在

while

循环运行时无法按下另一个按钮

您可以查看创建编程循环的方法，该循环将保持GUI的响应性。下面是一个例子：

def callback(flag):
    global loop
    if flag is True:
        print('message')
        ... other logic ...
        # start the after method to call the callback every 100ms
        loop = root.after(100, callback, True)
    else:
        # cancel the after method if the flag is False
        root.after_cancel(loop)

root = Tk()

# use a lambda expression to pass arg to callback in button commands
Button(root, text='start', command=lambda: callback(True)).pack()
Button(root, text='stop', command=lambda: callback(False)).pack()

mainloop()

您还可以将GUI和业务保持在单独的线程中，但这通常是需要设置的PITA。

after（）

方法通常同样有效