用Python语法调用函数

嘿，我正在用python 2.6编写一个小程序，我已经定义了 2个助手函数，几乎可以实现我想要的所有功能，例如

def helper1:
    ...


def helper2:
    ...

现在我的问题是，我想创建一个新函数，将两个函数合并到一个函数中，这样我就不必在shell中编写：

list(helper1(helper2(argument1,argument2)))

而是

function(argument1,argument2)

有没有捷径可走？我是python新手，还是需要更多的代码示例才能回答

如需任何提示或帮助，请提前联系Thanx

def function(arg1, arg2):
    return list(helper1(helper2(arg1, arg2)))

应该有用

function = lambda x, y: list(helper1(helper2(x, y)))

---

这是高阶函数compose的一个例子。躺在那里很方便

function = lambda x, y: list(helper1(helper2(x, y)))

def compose(*functions):
    """ Returns the composition of functions"""
    functions = reversed(functions)
    def composition(*args, **kwargs):
        func_iter = iter(functions)
        ret = next(func_iter)(*args, **kwargs)
        for f in func_iter:
            ret = f(ret)
        return ret
    return composition

现在可以将函数编写为

function1 = compose(list, helper1, helper2)
function2 = compose(tuple, helper3, helper4)
function42 = compose(set, helper4, helper2)

---

等等。

这是高阶函数组合的一个示例。躺在那里很方便

def compose(*functions):
    """ Returns the composition of functions"""
    functions = reversed(functions)
    def composition(*args, **kwargs):
        func_iter = iter(functions)
        ret = next(func_iter)(*args, **kwargs)
        for f in func_iter:
            ret = f(ret)
        return ret
    return composition

现在可以将函数编写为

function1 = compose(list, helper1, helper2)
function2 = compose(tuple, helper3, helper4)
function42 = compose(set, helper4, helper2)

等等