Python 如何找到基于权重的定制平均值,包括熊猫nan值的处理?

Python 如何找到基于权重的定制平均值,包括熊猫nan值的处理?,python,pandas,numpy,dataframe,data-science,Python,Pandas,Numpy,Dataframe,Data Science,我有一个数据帧df_ss_g as ent_id,WA,WB,WC,WD 123,0.045251836,0.614582906,0.225930615,0.559766482 124,0.722324239,0.057781167,,0.123603561 125,,0.361074325,0.768542766,0.080434134 126,0.085781742,0.698045853,0.763116684,0.029084545 127,0.909758657,,0.76099375

我有一个数据帧df_ss_g as

ent_id,WA,WB,WC,WD
123,0.045251836,0.614582906,0.225930615,0.559766482
124,0.722324239,0.057781167,,0.123603561
125,,0.361074325,0.768542766,0.080434134
126,0.085781742,0.698045853,0.763116684,0.029084545
127,0.909758657,,0.760993759,0.998406211
128,,0.32961283,,0.90038336
129,0.714585519,,0.671905291,
130,0.151888772,0.279261613,0.641133263,0.188231227
现在我必须计算基于权重的平均值(平均权重),即=
(WA*0.5+WB*1+WC*0.5+WD*1)/(0.5+1+0.5+1)

但是当我用下面的方法计算它的时候

df_ss_g['AVG_WEIGHTAGE']= df_ss_g.apply(lambda x:((x['WA']*0.5)+(x['WB']*1)+(x['WC']*0.5)+(x['WD']*1))/(0.5+1+0.5+1) , axis=1)
它输出为,即对于NaN值,它给出的NaN为平均值,权重为null,这是错误的。

我想要的是,在分母和分子中不应该考虑null e、 g

IIUC:


使用点积尝试此方法-

def av(t):
    #Define weights
    wt = [0.5, 1, 0.5, 1]
    
    #Create a vector with 0 for null and 1 for non null
    nulls = [int(i) for i in ~t.isna()]
    
    #Take elementwise products of the nulls vector with both weights and t.fillna(0)
    wt_new = np.dot(nulls, wt)
    t_new = np.dot(nulls, t.fillna(0))
    
    #return division
    return np.divide(t_new,wt_new)

df['WEIGHTED AVG'] = df.apply(av, axis=1)
df = df.reset_index()
print(df)

它归结为用
0
屏蔽
nan
值,这样它们就不会对权重或总和产生影响:

# this is the weights
weights = np.array([0.5,1,0.5,1])

# the columns of interest
s = df.iloc[:,1:]

# where the valid values are
mask = s.notnull()

# use `fillna` and then `@` for matrix multiplication
df['AVG_WEIGHTAGE'] = (s.fillna(0) @ weights) / (mask@weights)

如果您使用
fillna()
并将所有NaN填充为0会怎么样?@user13802115它将不起作用,因为通过使用fillna()它被视为分母…这使得平均值错误当我实现您的逻辑时,我得到了以下错误值错误:int()的文本无效,以10为底:“WA”
def av(t):
    #Define weights
    wt = [0.5, 1, 0.5, 1]
    
    #Create a vector with 0 for null and 1 for non null
    nulls = [int(i) for i in ~t.isna()]
    
    #Take elementwise products of the nulls vector with both weights and t.fillna(0)
    wt_new = np.dot(nulls, wt)
    t_new = np.dot(nulls, t.fillna(0))
    
    #return division
    return np.divide(t_new,wt_new)

df['WEIGHTED AVG'] = df.apply(av, axis=1)
df = df.reset_index()
print(df)
   ent_id        WA        WB        WC        WD  WEIGHTED AVG
0     123  0.045252  0.614583  0.225931  0.559766      0.481844
1     124  0.722324  0.057781       NaN  0.123604      0.361484
2     125       NaN  0.361074  0.768543  0.080434      0.484020
3     126  0.085782  0.698046  0.763117  0.029085      0.525343
4     127  0.909759       NaN  0.760994  0.998406      1.334579
5     128       NaN  0.329613       NaN  0.900383      0.614998
6     129  0.714586       NaN  0.671905       NaN      1.386491
7     130  0.151889  0.279262  0.641133  0.188231      0.420172
# this is the weights
weights = np.array([0.5,1,0.5,1])

# the columns of interest
s = df.iloc[:,1:]

# where the valid values are
mask = s.notnull()

# use `fillna` and then `@` for matrix multiplication
df['AVG_WEIGHTAGE'] = (s.fillna(0) @ weights) / (mask@weights)