Python 一个属性正在更新,另一个属性未更新
我正在阅读,并试图进行练习。这项工作是: 更新填充脚本,使Python类别有128个视图和64个喜欢,Django类别有64个视图和32个喜欢,而其他框架类别有32个视图和16个喜欢 所以,我在人口脚本中也做了同样的事情:Python 一个属性正在更新,另一个属性未更新,python,django,Python,Django,我正在阅读,并试图进行练习。这项工作是: 更新填充脚本,使Python类别有128个视图和64个喜欢,Django类别有64个视图和32个喜欢,而其他框架类别有32个视图和16个喜欢 所以,我在人口脚本中也做了同样的事情: def add_cat(name,likes,views): c = Category.objects.get_or_create(name=name)[0] c.likes = likes print c.likes c.views = views return c 整个
def add_cat(name,likes,views):
c = Category.objects.get_or_create(name=name)[0]
c.likes = likes
print c.likes
c.views = views
return c
整个剧本是:
import os
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'tango_with_django_project.settings')
import django
django.setup()
from rango.models import Category, Page
def populate():
python_cat = add_cat('Python',64,128)
add_page(cat=python_cat,
title="Official Python Tutorial",
url="http://docs.python.org/2/tutorial/")
add_page(cat=python_cat,
title="How to Think like a Computer Scientist",
url="http://www.greenteapress.com/thinkpython/")
add_page(cat=python_cat,
title="Learn Python in 10 Minutes",
url="http://www.korokithakis.net/tutorials/python/")
django_cat = add_cat("Django",32,64)
add_page(cat=django_cat,
title="Official Django Tutorial",
url="https://docs.djangoproject.com/en/1.5/intro/tutorial01/")
add_page(cat=django_cat,
title="Django Rocks",
url="http://www.djangorocks.com/")
add_page(cat=django_cat,
title="How to Tango with Django",
url="http://www.tangowithdjango.com/")
frame_cat = add_cat("Other Frameworks",16,32)
add_page(cat=frame_cat,
title="Bottle",
url="http://bottlepy.org/docs/dev/")
add_page(cat=frame_cat,
title="Flask",
url="http://flask.pocoo.org")
# Print out what we have added to the user.
for c in Category.objects.all():
for p in Page.objects.filter(category=c):
print "- {0} - {1}".format(str(c), str(p))
def add_page(cat, title, url, views=0):
p = Page.objects.get_or_create(category=cat, title=title)[0]
p.url=url
p.views=views
p.save()
return p
def add_cat(name,likes,views):
c = Category.objects.get_or_create(name=name)[0]
c.likes = likes
print c.likes
c.views = views
return c
# Start execution here!
if __name__ == '__main__':
print "Starting Rango population script..."
populate()
现在,我要打印喜欢和视图的值:
>>> c = Category.objects.get(pk = 3)
>>> c
<Category: Python>
>>> c.likes
0
>>> c.views
128
>>>
>c=Category.objects.get(pk=3)
>>>c
>>>c.喜欢
0
>>>c.观点
128
>>>
当视图更新时,likes的值不会更改 您需要保存对象,有关详细信息,请查看
请解释一下。为什么我需要为喜欢而不是视图保存?您正在保存
c
对象(它同时保存likes
和views
每个对象的属性),但是不保存视图就可以了。为什么它适用于视图?@learner通过执行c.likes=likes
和c.views=views
您正在为该范围更新c
对象,您没有持久化该数据,您需要调用.save()
方法在数据库上写入并在更新后检索更新的值。
def add_cat(name,likes,views):
c = Category.objects.get_or_create(name=name)[0]
c.likes = likes
print c.likes
c.views = views
c.save()
return c