Python QThreadPool按顺序运行而不是并行运行,是什么导致我的代码线程不能并行运行?

Python QThreadPool按顺序运行而不是并行运行,是什么导致我的代码线程不能并行运行?,python,python-3.x,multithreading,pyqt,pyqt5,Python,Python 3.x,Multithreading,Pyqt,Pyqt5,我想并行运行pyqt5 QThreads,但我的代码似乎是按顺序运行的。有人能告诉我如何并行运行QThreads吗 我的代码的输出:我希望它并行运行,而不是按顺序运行 Multithreading with maximum 4 threads You pressed the Test button Job 1 Job 2 Job 3 Job 4 Done. THREAD COMPLETE! 代码: 您必须为每个任务创建一个Worker(QRunnable),在您的情况下,您只为其创建了一个W

我想并行运行pyqt5 QThreads,但我的代码似乎是按顺序运行的。有人能告诉我如何并行运行QThreads吗

我的代码的输出:我希望它并行运行,而不是按顺序运行

Multithreading with maximum 4 threads
You pressed the Test button
Job 1
Job 2
Job 3
Job 4
Done.
THREAD COMPLETE!

代码:


您必须为每个任务创建一个Worker(QRunnable),在您的情况下,您只为其创建了一个Worker,任务将按顺序执行:

from PyQt5 import QtCore, QtGui, QtWidgets

import time
import traceback, sys

uart_result = ['1','2', '3', '4', '5', '6']

#Running all these methods in parallel
@QtCore.pyqtSlot()
def run1():
    print("Job 1")
    return uart_result

@QtCore.pyqtSlot()
def run2():
    print("Job 2")
    return uart_result

@QtCore.pyqtSlot()
def run3():
    print("Job 3")
    return uart_result

@QtCore.pyqtSlot()
def run4():
    print("Job 4")
    return uart_result

class WorkerSignals(QtCore.QObject):
    finished = QtCore.pyqtSignal()
    error = QtCore.pyqtSignal(tuple)
    result = QtCore.pyqtSignal(object)
    progress = QtCore.pyqtSignal(int)


class Worker(QtCore.QRunnable):
    def __init__(self, fn, *args, **kwargs):
        super(Worker, self).__init__()
        self.fn = fn
        self.args = args
        self.kwargs = kwargs
        self.signals = WorkerSignals()
    def run(self):
        try:
            result = self.fn(*self.args, **self.kwargs)
        except:
            traceback.print_exc()
            exctype, value = sys.exc_info()[:2]
            self.signals.error.emit((exctype, value, traceback.format_exc()))
        else:
            self.signals.result.emit(result)  # Return the result of the processing
        finally:
            self.signals.finished.emit()  # Done



class MainWindow(QtWidgets.QMainWindow):
    def __init__(self, *args, **kwargs):
        super(MainWindow, self).__init__(*args, **kwargs)
        b = QtWidgets.QPushButton("START!")
        b.pressed.connect(self.runner)

        w = QtWidgets.QWidget()
        layout = QtWidgets.QVBoxLayout(w)
        layout.addWidget(b)
        self.setCentralWidget(w)

    def print_output(self, uart_list):
        print(uart_list)

    def thread_complete(self):
        print("THREAD COMPLETE!")

    def runner(self):
        thread_pool = QtCore.QThreadPool.globalInstance()
        print("Multithreading with maximum %d threads" % thread_pool.maxThreadCount())
        print("You pressed the Test button")
        for task in (run1, run2, run3, run4):
            worker = Worker(task)
            worker.signals.result.connect(self.print_output)
            worker.signals.finished.connect(self.thread_complete)
            thread_pool.start(worker)

if __name__ == '__main__':
    import sys
    app = QtWidgets.QApplication(sys.argv)
    window = MainWindow()
    window.show()
    sys.exit(app.exec_())

您混淆了并发的概念:一个是多线程,另一个是并行。并发的思想是执行多个任务,在它们之间有几种策略:多线程,其中多个任务在同一进程中执行,也就是说,它们共享同一内存;并行,其中任务使用非共享资源执行,例如。Qt不支持并行,但支持多线程。我建议您查看有关不同并发类型的信息您期望的输出是什么?如果您意识到4个任务在另一个线程中按顺序运行,因此打印是按顺序进行的,我看不到任何错误。好的,谢谢您提供的信息。我的理解是错误的。我知道线程在同一进程中运行,并共享堆栈和堆等内存。好的,我现在知道QT不支持并行性。我希望输出像job1、job4、Job3、job2。在pthreads中,线程不是按顺序运行的,而是以随机方式运行的,这正是我所期望的。您创建了多少线程?您只创建了一个线程,所有任务都在同一个线程中执行,如果您创建了4个线程,您将得到您想要的完美,您再次清除了我对使用QRunnable的混淆。你真的很棒。
from PyQt5 import QtCore, QtGui, QtWidgets

import time
import traceback, sys

uart_result = ['1','2', '3', '4', '5', '6']

#Running all these methods in parallel
@QtCore.pyqtSlot()
def run1():
    print("Job 1")
    return uart_result

@QtCore.pyqtSlot()
def run2():
    print("Job 2")
    return uart_result

@QtCore.pyqtSlot()
def run3():
    print("Job 3")
    return uart_result

@QtCore.pyqtSlot()
def run4():
    print("Job 4")
    return uart_result

class WorkerSignals(QtCore.QObject):
    finished = QtCore.pyqtSignal()
    error = QtCore.pyqtSignal(tuple)
    result = QtCore.pyqtSignal(object)
    progress = QtCore.pyqtSignal(int)


class Worker(QtCore.QRunnable):
    def __init__(self, fn, *args, **kwargs):
        super(Worker, self).__init__()
        self.fn = fn
        self.args = args
        self.kwargs = kwargs
        self.signals = WorkerSignals()
    def run(self):
        try:
            result = self.fn(*self.args, **self.kwargs)
        except:
            traceback.print_exc()
            exctype, value = sys.exc_info()[:2]
            self.signals.error.emit((exctype, value, traceback.format_exc()))
        else:
            self.signals.result.emit(result)  # Return the result of the processing
        finally:
            self.signals.finished.emit()  # Done



class MainWindow(QtWidgets.QMainWindow):
    def __init__(self, *args, **kwargs):
        super(MainWindow, self).__init__(*args, **kwargs)
        b = QtWidgets.QPushButton("START!")
        b.pressed.connect(self.runner)

        w = QtWidgets.QWidget()
        layout = QtWidgets.QVBoxLayout(w)
        layout.addWidget(b)
        self.setCentralWidget(w)

    def print_output(self, uart_list):
        print(uart_list)

    def thread_complete(self):
        print("THREAD COMPLETE!")

    def runner(self):
        thread_pool = QtCore.QThreadPool.globalInstance()
        print("Multithreading with maximum %d threads" % thread_pool.maxThreadCount())
        print("You pressed the Test button")
        for task in (run1, run2, run3, run4):
            worker = Worker(task)
            worker.signals.result.connect(self.print_output)
            worker.signals.finished.connect(self.thread_complete)
            thread_pool.start(worker)

if __name__ == '__main__':
    import sys
    app = QtWidgets.QApplication(sys.argv)
    window = MainWindow()
    window.show()
    sys.exit(app.exec_())