使用python发送gmail失败

1。pip错误

是的

然后它说

Could not find a version that satisfies the requirement smtplib (from versions: ) No matching distribution found for smtplib

我证实了这一点

pip install youtube_dl

工作。所以这可能不是皮普的问题

2。导入错误

无论如何，我运行的代码是

import smtplib

GMAIL_USERNAME = "something"
GMAIL_PASSWORD = "something"
recipient = "something"
body_of_email = "body"
email_subject = "ha"

# The below code never changes, though obviously those variables need values.
session = smtplib.SMTP('smtp.gmail.com', 587)
session.ehlo()
session.starttls()
session.login(GMAIL_USERNAME, GMAIL_PASSWORD)


headers = "\r\n".join(["from: " + GMAIL_USERNAME,
                       "subject: " + email_subject,
                       "to: " + recipient,
                       "mime-version: 1.0",
                       "content-type: text/html"])

# body_of_email can be plaintext or html!                    
content = headers + "\r\n\r\n" + body_of_email
session.sendmail(GMAIL_USERNAME, recipient, content)

但Anaconda提示显示了错误

ImportError: cannot import name 'SMTP'

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我搞不懂为什么会发生这种奇怪的事情。

你支持代理吗？@crisron你是什么意思？代理？，我是说代理server@crisron我不会用那种东西。我在家里的桌面上用足够快的互联网连接运行这段代码。这就是此代码失败的原因吗？请尝试

pip安装--pre-smtplib

。

ImportError: cannot import name 'SMTP'