Python 如何防止TypeError:+；的操作数类型不受支持：'；非类型'；和'；浮动'；

如何防止

add

函数引发的

TypeError

发生

#TypeError:不支持+：“非类型”和“浮点”的操作数类型

---

---

在函数

number_1

中，您忘记返回值

另一方面，为什么要使用两个不同的函数来做相同的事情？ 我做了一些清理，并添加了一些评论以澄清问题

def input_number(prompt):
    while True:
        x = input(prompt)
        try:
            # You don't need to cast to float twice. Just do it in the return statement. 
            # If there's something wrong, the exception is raised before the return

            return float(x)

            # A break here is useless because return will prevent the while loop from continuing running
        except ValueError:
            print("\"{0}\" is not a number\nEnter again".format(x))

def add(p,q):
    return p + q

num1 = input_number("Enter num1: ")
num2 = input_number("Enter num2: ")

num3 = add(num1, num2)

print("Result: {}".format(num3))

def input_number(prompt):
    while True:
        x = input(prompt)
        try:
            # You don't need to cast to float twice. Just do it in the return statement. 
            # If there's something wrong, the exception is raised before the return

            return float(x)

            # A break here is useless because return will prevent the while loop from continuing running
        except ValueError:
            print("\"{0}\" is not a number\nEnter again".format(x))

def add(p,q):
    return p + q

num1 = input_number("Enter num1: ")
num2 = input_number("Enter num2: ")

num3 = add(num1, num2)

print("Result: {}".format(num3))