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Python 如何解决pyspark中由于微调功能导致的数据不匹配错误?_Python_Apache Spark_Pyspark - Fatal编程技术网

Python 如何解决pyspark中由于微调功能导致的数据不匹配错误?

Python 如何解决pyspark中由于微调功能导致的数据不匹配错误?,python,apache-spark,pyspark,Python,Apache Spark,Pyspark,当我运行此代码时,它会给我一个错误: df1 = (df.withColumn("columnName_{}".format(columnName), psf.lit(columnName)) .withColumn("{}_not_null".format(columnName), psf.when((psf.col(columnName).isNotNull()& psf.trim(psf.col(columnName))!= psf.

当我运行此代码时,它会给我一个错误:

df1 = (df.withColumn("columnName_{}".format(columnName), psf.lit(columnName))
    .withColumn("{}_not_null".format(columnName), psf.when((psf.col(columnName).isNotNull()& psf.trim(psf.col(columnName))!= psf.lit('') ),1))


有人能帮我解决这个错误吗?

您需要将第二个条件括在括号中,因为
&
的求值优先级高于
=

cannot resolve '((`Address` IS NOT NULL) AND trim(`Address`))' due to data type mismatch: differing types in '((`Address` IS NOT NULL) AND trim(`Address`))' (boolean and string)
df1 = df.withColumn(
    "columnName_{}".format(columnName),
    psf.lit(columnName)
).withColumn(
    "{}_not_null".format(columnName),
    psf.when(
        psf.col(columnName).isNotNull() &
        (psf.trim(psf.col(columnName)) != psf.lit(''))
    , 1)
)