Python 如何剪切匹配的字符串

我想剪下匹配的字符串

我考虑在[R.FixITER（''）]中使用[m启动（）]来获得GET索引。< /P> 但我认为存在的方式比这更好

例如，我想剪切“页眉”和“页脚”之间的字符串

请告诉我

import re

def returnmatches(text,headers,footers):
    """headers is a list of headers
footers is a list of footers
text is the text to search"""
    for header,footer in zip(headers,footers):
        pattern = r"{}\w+?{}".format(header,footer)
        try:
            yield re.search(pattern,input_text).group()
        except AttributeError:
            # handle no match
            pass

或者：

text = "header1svdijfooter1ccsdheader2cdijhfooter2"
headers = ["header1", "header2"]
footers = ["footer1", "footer2"]

import re

matches = [re.search(r"{}\w+?{}".format(header,footer),text).group() for header,footer in zip(headers,footers) if re.search(r"{}\w+?{}".format(header,footer),text)]

---

可以使用列表在一行中完成计算：

s = "header1svdijfooter1ccsdheader2cdijhfooter2"
headers = {"one": "header1", "two": "header2"}
footers = {"one": "footer1", "two": "footer2"}
out = [re.search('({}.*?{})'.format(headers[k], footers[k]), s).group(0) for k in sorted(headers.keys())]

如上所述，根据示例，假设存在且仅存在一个匹配组

或者，如果喜欢循环：

s = "header1svdijfooter1ccsdheader2cdijhfooter2"
headers = {"one": "header1", "two": "header2"}
footers = {"one": "footer1", "two": "footer2"}
out=[]
for k in sorted(headers.keys()):
    out.extend(re.search('({}.*?{})'.format(headers[k], footers[k]), s).groups())
print out

上述操作产生输出：

['header1svdijfooter1', 'header2cdijhfooter2']

无需回复：

str = "header1svdijfooter1ccsdheader2cdijhfooter2"
result = []
capture=False
currentCapture = ""
for i in range(len(str)):
    if str[i:].startswith("header1") or str[i:].startswith("header2"):
        currentCapture = ""
        capture=True
    elif str[:i].endswith("footer1") or str[:i].endswith("footer2"):
        capture=False
        result.append(currentCapture)
        currentCapture = ""
    if capture:
        currentCapture = currentCapture+str[i]
if currentCapture:
    result.append(currentCapture)

print result

输出：

['header1svdijfooter1', 'header2cdijhfooter2']

---

请编辑您的帖子以修复

页眉

和

页脚

。以这种方式声明它们是一个编译错误。您的意思是创建字典吗？使用

dict（）

或

{}

这是正则表达式的一个很好的用法。你会考虑编辑你的答案来包含格式化的字符串，而不使用<代码> %<代码>格式操作符吗？没有提到空格在比赛中是特别的？@dementedhedgehog他的例子中没有任何空格，所以我不想在他的例子中包括任何他没有明确提到的内容。

str = "header1svdijfooter1ccsdheader2cdijhfooter2"
result = []
capture=False
currentCapture = ""
for i in range(len(str)):
    if str[i:].startswith("header1") or str[i:].startswith("header2"):
        currentCapture = ""
        capture=True
    elif str[:i].endswith("footer1") or str[:i].endswith("footer2"):
        capture=False
        result.append(currentCapture)
        currentCapture = ""
    if capture:
        currentCapture = currentCapture+str[i]
if currentCapture:
    result.append(currentCapture)

print result

['header1svdijfooter1', 'header2cdijhfooter2']