Python 如何绘制具有非恒定半径的圆柱体
我已经编写了生成具有固定半径的圆柱体的代码:Python 如何绘制具有非恒定半径的圆柱体,python,matplotlib,Python,Matplotlib,我已经编写了生成具有固定半径的圆柱体的代码: import numpy as np from matplotlib import pyplot as plt from mpl_toolkits.mplot3d import Axes3D from math import sin, cos, pi fig = plt.figure() ax = fig.add_subplot(111, projection='3d') theta = np.linspace(-2*pi,2*pi, 600)
import numpy as np
from matplotlib import pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
from math import sin, cos, pi
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
theta = np.linspace(-2*pi,2*pi, 600)
Z = np.linspace(0,1,700)
Z,theta = np.meshgrid(Z, theta)
R = 0.1
X = (R*np.cos(theta))
Y = (R*np.sin(theta))
ax.plot_surface(X,Y,Z,linewidth = 0,facecolor = 'r', shade = True, alpha = 0.6)
plt.show()
如何更改此设置,使圆柱体半径可以变化。例如,半径从圆柱体一端的0.1开始,绘制的每个连续“圆”的半径比之前多0.01?换句话说,我想把不同半径的圆“连接”在一起,形成一个半径不恒定的圆柱体。Changed
R=np.linspace(0,1700)
您还可以尝试使用类似于
R=np.sin(np.linspace(0,1700)*4)+1的函数,谢谢!我很快就会接受(一旦时间限制达到)Nice,然后你只需添加到R中,比如R=np.linspace(0,1700)+2
,以使圆锥体打开。顺便说一句,当我试图解决这个问题时,我做了R=np.arange(0600*700)。重塑(600700)
:D有趣的结果
import numpy as np
from matplotlib import pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
from math import sin, cos, pi
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
theta = np.linspace(-2*pi,2*pi, 600)
Z = np.linspace(0,1,700)
Z,theta = np.meshgrid(Z, theta)
R = np.linspace(0,1,700)
X = (R*np.cos(theta))
Y = (R*np.sin(theta))
ax.plot_surface(X,Y,Z,linewidth = 0,facecolor = 'r', shade = True, alpha = 0.6)
plt.show()