Python 我一直收到缩进错误,我不应该';不可能
每当我在CMD中运行我的程序时,就会出现缩进错误。对我来说,整个程序的缩进看起来很完美,所以我完全不知道为什么会收到错误 CMD错误:Python 我一直收到缩进错误,我不应该';不可能,python,selenium,beautifulsoup,urllib2,xlsxwriter,Python,Selenium,Beautifulsoup,Urllib2,Xlsxwriter,每当我在CMD中运行我的程序时,就会出现缩进错误。对我来说,整个程序的缩进看起来很完美,所以我完全不知道为什么会收到错误 CMD错误: scraper9.py", line 50 browser.get(url2) ^ IndentationError: unexpected unindent 我已经完全删除了所有缩进,并一行一行地重新缩进,以到达当前迭代,但我仍然会出错 导入操作系统 导入系统 导入csv 从bs
scraper9.py", line 50
browser.get(url2)
^
IndentationError: unexpected unindent
我已经完全删除了所有缩进,并一行一行地重新缩进,以到达当前迭代,但我仍然会出错
导入操作系统
导入系统
导入csv
从bs4导入BeautifulSoup
导入urllib2
导入xlsxwriter
从selenium导入webdriver
reload(sys)
sys.setdefaultencoding("utf8")
key_stats_on_main = ["Market Cap", "PE Ratio (TTM)"]
key_stats_on_stat = ["Enterprise Value", "Trailing P/E"]
stocks_arr =[]
pfolio_file = open("tickers.csv", "r")
for line in pfolio_file:
indv_stock_arr = line.strip().split(",")
stocks_arr.append(indv_stock_arr)
print(stocks_arr)
browser = webdriver.PhantomJS()
stock_info_arr = []
for stock in stocks_arr:
stock_info = []
ticker = stock[0]
stock_info.append(ticker)
url="https://finance.yahoo.com/quote/{0}?p={0}".format(ticker)
url2="https://finance.yahoo.com/quote/{0}/key-statistics?p={0}".format(ticker)
browser.get(url)
innerHTML = browser.execute_script("return document.body.innerHTML")
soup = BeautifulSoup(innerHTML, "html.parser")
for stat in key_stats_on_main:
page_stat1 = soup.find(text = stat)
try:
page_row1 = page_stat1.find_parent("tr")
try:
page_statnum1 = page_row1.find_all("span")[1].contents[1]
except:
page_statnum1 = page_row1.find_all("td")[1].contents[0]
except:
print("Invalid parent for this element")
page_statnum1 = "N/A"
stock_info.append(page_statnum1)
browser.get(url2)
innerHTML2 = browser.execute_script("return document.body.innerHTML2")
soup2 = BeautifulSoup(innerHTML2, "html.parser")
for stat in key_stats_on_stat:
page_stat2 = soup2.find(text=stat)
try:
page_row2 = page_stat2.find_parent("tr")
try:
page_statnum2 = page_row2.find_all("span")[1].contents[0]
except:
page_statnum2 = page_row2.find_all("td")[1].content[0]
except:
print("Invalid pareent for this element")
page_statnum2 = "N/A"
stock_info.append(page_statnum2)
stock_info_arr.append(stock_info)
print(stock_info_arr)
key_stats_on_main.extend(key_stats_on_stat)
workbook = xlsxwriter.Workbook("Stocks01.xlsx")
worksheet = workbook.add_worksheet()
row = 0
col = 2
for stat in key_stats_on_main:
worksheet.write(row, col, stat)
col +=1
row = 1
col = 0
for our_stock in stock_info_arr:
col = 0
for info_bit in our_stock:
worksheet.write(row, col, info_bit)
col += 1
row += 1
workbook.close()
print("Script completed")
我希望代码执行时不会出现错误
它出错了。我太迷路了。你的
尝试:
缺少,除了:
或最后:
for stat in key_stats_on_main:
page_stat1 = soup.find(text = stat)
try: # <--------------- this one here
page_row1 = page_stat1.find_parent("tr")
try:
page_statnum1 = page_row1.find_all("span")[1].contents[1]
except:
page_statnum1 = page_row1.find_all("td")[1].contents[0]
except:
print("Invalid parent for this element")
page_statnum1 = "N/A"
stock_info.append(page_statnum1)
# <---------------- needs something here
browser.get(url2)
试试看
顺便说一句,您应该减少try:
子句中的代码大小,只捕获您正在处理的异常。在您的情况下,属性错误(如果.contents
失败)将被第一个捕获,除了:
。更好:
try:
found = page_row1.find_all("span")
index = 1
except XError: # should be the one .find_all() can raise
found = page_row1.find_all("td")
index = 0
page_statnum1 = found[1].contents[index]
对于外部的尝试类似的方法
/,除了
这样,您就不会掩盖您从未打算处理的其他异常。如果你这样做,你将很难找出哪里出了问题,所以要避免它。你的尝试:
缺少,除了:
或最后:
for stat in key_stats_on_main:
page_stat1 = soup.find(text = stat)
try: # <--------------- this one here
page_row1 = page_stat1.find_parent("tr")
try:
page_statnum1 = page_row1.find_all("span")[1].contents[1]
except:
page_statnum1 = page_row1.find_all("td")[1].contents[0]
except:
print("Invalid parent for this element")
page_statnum1 = "N/A"
stock_info.append(page_statnum1)
# <---------------- needs something here
browser.get(url2)
试试看
顺便说一句,您应该减少try:
子句中的代码大小,只捕获您正在处理的异常。在您的情况下,属性错误(如果.contents
失败)将被第一个捕获,除了:
。更好:
try:
found = page_row1.find_all("span")
index = 1
except XError: # should be the one .find_all() can raise
found = page_row1.find_all("td")
index = 0
page_statnum1 = found[1].contents[index]
对于外部的尝试类似的方法
/,除了
这样,您就不会掩盖您从未打算处理的其他异常。如果你这样做,你将很难找出哪里出了问题,所以要避免它。你是在混合空格和制表符吗?尝试使用编辑器/IDE的工具规范化空白。是否混合了空格和制表符?尝试使用编辑器/IDE的工具来规范化空白。哇,该死。这里有一堂关于编码的迷你课。非常感谢你!哇,该死。这里有一堂关于编码的迷你课。非常感谢你!