Python 加入“,”&引用;从后面打3个回合后
我只是试着在每3个字符之间显示一个“,” 我试了一下:Python 加入“,”&引用;从后面打3个回合后,python,range,python-2.5,Python,Range,Python 2.5,我只是试着在每3个字符之间显示一个“,” 我试了一下: players = ','.join([player[i:i+3] for i in range(0, len(player), 3)]) rankedplayers = ','.join([ranked[i:i+3] for i in range(0, len(ranked), 3)]) points = ','.join([totalpoints[i:i+3] for i in range(0, len(totalpoints), 3)
players = ','.join([player[i:i+3] for i in range(0, len(player), 3)])
rankedplayers = ','.join([ranked[i:i+3] for i in range(0, len(ranked), 3)])
points = ','.join([totalpoints[i:i+3] for i in range(0, len(totalpoints), 3)])
但它只从左到右开始,我怎么能从后面从右到左开始呢
编辑:
比如说
player = 9502
ranked = 2040
totalpoints = 12390
其结果是:
player 950,2
ranked 204,0
totalpoints = 123,90
应该是:
player = 9,502
ranked = 2,040
totalpoints = 12,390
这个
regex
正好满足您的需要:
(/(\d)(?=(?:\d{3})+$)/g,$1')
最好使用
replace
方法。您可以从另一侧反转范围,如下所示:
player = ','.join([player[i:i+3] for i in reversed(range(0, len(player), 3))])
但对于使用逗号分组数字,您真正想要做的是:
player = "{:,}".format(int(player))
你能给我们一些示例输入和预期输出吗?@MartijnPieters编辑!Thanksi在这里提出了一种方法——如果您愿意,您可以根据自己的代码调整它@埃兰的答案更好:)