Python 我写了这段代码，但我的输出不是2D格式，我不知道'；我不知道如何修理它

我完整地编写了代码，但是我没有从问题中得到预期的结果。当我输入值时，由于某种原因，它们不在2D列表中

功能：

def matrix_rotate_right(a):

    b = []

    for i in range(len(a[0])):
        b.append([])
        for j in range(len(a) - 1, -1, -1):
            b[i].append(a[j][i])

    return b

Write and test the following function:

def matrix_rotate_right(a):
    """
    -------------------------------------------------------
    Returns a copy of a 2D matrix rotated to the right.
    a must be unchanged.
    Use: b = matrix_rotate_right(a)
    -------------------------------------------------------
    Parameters:
        a - a 2D list of values (2d list of int/float)
    Returns:
        b - the rotated 2D list of values (2D list of int/float)
    -------------------------------------------------------
    """
Add this function to the PyDev module functions.py. Test it from t01.py.

Given the following 2D matrix:

 1  2  3
 4  5  6
 7  8  9
10 11 12
Rotating it to the right produces the following matrix:

10  7  4  1
11  8  5  2
12  9  6  3

[[10, 7, 4, 1], [11, 8, 5, 2], [12, 9, 6, 3]]

t01.py

a = [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
b = matrix_rotate_right(a)
print(b)

问题：

def matrix_rotate_right(a):

    b = []

    for i in range(len(a[0])):
        b.append([])
        for j in range(len(a) - 1, -1, -1):
            b[i].append(a[j][i])

    return b

Write and test the following function:

def matrix_rotate_right(a):
    """
    -------------------------------------------------------
    Returns a copy of a 2D matrix rotated to the right.
    a must be unchanged.
    Use: b = matrix_rotate_right(a)
    -------------------------------------------------------
    Parameters:
        a - a 2D list of values (2d list of int/float)
    Returns:
        b - the rotated 2D list of values (2D list of int/float)
    -------------------------------------------------------
    """
Add this function to the PyDev module functions.py. Test it from t01.py.

Given the following 2D matrix:

 1  2  3
 4  5  6
 7  8  9
10 11 12
Rotating it to the right produces the following matrix:

10  7  4  1
11  8  5  2
12  9  6  3

[[10, 7, 4, 1], [11, 8, 5, 2], [12, 9, 6, 3]]

运行示例：

def matrix_rotate_right(a):

    b = []

    for i in range(len(a[0])):
        b.append([])
        for j in range(len(a) - 1, -1, -1):
            b[i].append(a[j][i])

    return b

Write and test the following function:

def matrix_rotate_right(a):
    """
    -------------------------------------------------------
    Returns a copy of a 2D matrix rotated to the right.
    a must be unchanged.
    Use: b = matrix_rotate_right(a)
    -------------------------------------------------------
    Parameters:
        a - a 2D list of values (2d list of int/float)
    Returns:
        b - the rotated 2D list of values (2D list of int/float)
    -------------------------------------------------------
    """
Add this function to the PyDev module functions.py. Test it from t01.py.

Given the following 2D matrix:

 1  2  3
 4  5  6
 7  8  9
10 11 12
Rotating it to the right produces the following matrix:

10  7  4  1
11  8  5  2
12  9  6  3

[[10, 7, 4, 1], [11, 8, 5, 2], [12, 9, 6, 3]]

我得到的输出：

def matrix_rotate_right(a):

    b = []

    for i in range(len(a[0])):
        b.append([])
        for j in range(len(a) - 1, -1, -1):
            b[i].append(a[j][i])

    return b

Write and test the following function:

def matrix_rotate_right(a):
    """
    -------------------------------------------------------
    Returns a copy of a 2D matrix rotated to the right.
    a must be unchanged.
    Use: b = matrix_rotate_right(a)
    -------------------------------------------------------
    Parameters:
        a - a 2D list of values (2d list of int/float)
    Returns:
        b - the rotated 2D list of values (2D list of int/float)
    -------------------------------------------------------
    """
Add this function to the PyDev module functions.py. Test it from t01.py.

Given the following 2D matrix:

 1  2  3
 4  5  6
 7  8  9
10 11 12
Rotating it to the right produces the following matrix:

10  7  4  1
11  8  5  2
12  9  6  3

[[10, 7, 4, 1], [11, 8, 5, 2], [12, 9, 6, 3]]

---

你的4个功能实现了你想要的

您只需要格式化输出

def matrix_rotate_right(a):

    b = []

    for i in range(len(a[0])):
        b.append([])
        for j in range(len(a) - 1, -1, -1):
            b[i].append(a[j][i])

    return b
a = [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
b = matrix_rotate_right(a)
for tuple in b:
    print(format(' '.join(map(str,tuple))))

---

在我看来，你已经归还了你想要的东西？这看起来像是一个漂亮的印刷品。试试看，你的任务就是旋转矩阵。它如何打印是无关紧要的。你的代码可以工作。