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URL UTF-8解码Python_Python_Utf 8_Character Encoding - Fatal编程技术网
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  • URL UTF-8解码Python

URL UTF-8解码Python

python utf-8 character-encoding

URL UTF-8解码Python,python,utf-8,character-encoding,Python,Utf 8,Character Encoding,我有一些URL格式的数据，我想用Python对其进行解码。我尝试了（被接受的）答案，但仍然没有得到正确的解码。我的代码如下： import urllib2 name = '%D0%BD%D0%BE%D1%82%D0%B8%D1%84%D0%B8%D0%BA%D0%B0%D1%82%D0%BE%D1%80-%D0%BE%D0%BB%D0%B8%D0%BC%D0%BF%D0%B8%D0%B9%D1%81%D0%BA%D0%B8%D1%85-%D0%B8' print urllib2.unquot

我有一些URL格式的数据，我想用Python对其进行解码。我尝试了（被接受的）答案，但仍然没有得到正确的解码。我的代码如下：

import urllib2

name = '%D0%BD%D0%BE%D1%82%D0%B8%D1%84%D0%B8%D0%BA%D0%B0%D1%82%D0%BE%D1%80-%D0%BE%D0%BB%D0%B8%D0%BC%D0%BF%D0%B8%D0%B9%D1%81%D0%BA%D0%B8%D1%85-%D0%B8'

print urllib2.unquote(urllib2.quote(name.encode("utf8"))).decode("utf8")
这应该打印
D0%BD%D0%BE%D1%82%D0%B8%D1%84%D0%B8%D0%BA%D0%B0%D1%82%D0%D0%80%D0%D0%80%D0%BB%D0%B8%D0%B8%D0%BA%D0%D0%D0%80%D0%BE%D0%BB%D0%B8%D0%B8%D0%D0%B8%D0%B8%D0%B8%D0%B8%D0%B8%D0%B8

所以我又试着取消引用

打印urlib2.unquote（urlib2.unquote（urlib2.quote（name.encode（“utf8”））））.decode（“utf8”））

但它给了我一个


我不知道为什么会这样。有人能解释一下我哪里做错了，我该如何纠正我的错误吗？
引用/取消引用操作太多：您得到的UTF-8字符串已经是URL编码的，为什么要再次对其进行UTF-8和URL编码


unquoted = urllib.unquote(name)
print unquoted.decode('utf-8')
# нотификатор-олимпийских-и