Python 如何在tkinter中将用户输入目录作为函数返回？

我只是在学习Python，我正在尝试构建一个程序，在指定位置解压文件，然后将其移动到另一个指定位置

我创建了一个函数，要求用户使用

filedialog.askopenfilename

搜索包含.zip文件的指定文件。然后应该将其存储起来，以便将其发送到另一个函数，该函数将解压文件，因为我不希望在收到位置后自动解压

我面临的问题是，我不确定如何传递和存储位置目录以供其他函数使用。还是有更好的方法

import tkinter as tk
from tkinter import filedialog
import zipfile
import os
import pathlib

root = tk.Tk()
root.geometry('450x350+350+150')  # setting the screen size
root.title('Unzip file')  # setting the title name


# Gets the user to choose the location of the zip file
def input_path():
    input_file_dir = filedialog.askdirectory()
    return input_file_dir  # how do I return this so that it can be passed to the extract_zip


# extracting the zip
def extract_zip(input_file_dir):
    os.chdir(input_file_dir)  # changing file directory to location of zip folder
    for file in os.listdir():  # get the list of files
        if zipfile.is_zipfile(file):  # if it is a zipfile, extract it
            with zipfile.ZipFile(file) as item:  # treat the file as a zip
                item.extractall()  # extract it in the working directory


# Setting the frame size to insert all our widgets
frame = tk.Frame(root, bg='black')
frame.pack(fill='both', expand=False)

# Setting the title in the frame
label = tk.Label(frame, text='Unzip Files', font='Arial 36 bold', fg='#948a54', bg='black', pady=50)
label.pack(side='top')

openFile = tk.Button(frame, text='Choose location of zip file', font='14', command=input_path)
openFile.pack(side='top')


unzipButton = tk.Button(frame, text='Unzip', width=19, font='14', command=extract_zip)
unzipButton.pack(side='top', pady=15)


root.mainloop()

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您可以使用

classes

和

self

变量，这些变量可以跨类中的函数访问。我已经更新了一些代码以使其能够工作，如果您不熟悉

类

和

self

，我将在下面提供一些链接，以了解它们的功能

import tkinter as tk
from tkinter import filedialog
import zipfile
import os
import pathlib

class unzip():

    def __init__(self):
        root = tk.Tk()
        root.geometry('450x350+350+150')  # setting the screen size
        root.title('Unzip file')  # setting the title name

        frame = tk.Frame(root, bg='black')
        frame.pack(fill='both', expand=False)

        # Setting the title in the frame
        label = tk.Label(frame, text='Unzip Files', font='Arial 36 bold', fg='#948a54', bg='black', pady=50)
        label.pack(side='top')

        openFile = tk.Button(frame, text='Choose location of zip file', font='14', command=self.input_path)
        openFile.pack(side='top')


        unzipButton = tk.Button(frame, text='Unzip', width=19, font='14', command=self.extract_zip)
        unzipButton.pack(side='top', pady=15)


        root.mainloop()

    # Gets the user to choose the location of the zip file
    def input_path(self):
        self.input_file_dir = filedialog.askdirectory()


    # extracting the zip
    def extract_zip(self):

        print(self.input_file_dir)
        os.chdir(self.input_file_dir)  # changing file directory to location of zip folder
        for file in os.listdir():  # get the list of files
            if zipfile.is_zipfile(file):  # if it is a zipfile, extract it
                with zipfile.ZipFile(file) as item:  # treat the file as a zip
                    item.extractall()  # extract it in the working directory



if __name__ == '__main__':
    unzip()

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您能提供与问题相关的代码以及您尝试过的内容吗？我已经添加了代码，但我认为没有任何好处