Python—从'；对于循环'；并合并成一个列表

我当前的输出是单个浮点数，不适合我的下一步：sum（）和statistics.mean（）。我曾尝试过嵌套列表理解，但当这不起作用时，我尝试了下一个嵌套循环，但我得到了相同的错误-TypeError:“float”对象不可iterable。通过使用[ss]，每个输出都会列出，但不会合并到单个列表中

感谢您的帮助。如果您需要澄清或有问题，请随时提问

import pandas as pd
import numpy as np
import math
import statistics

frame=[bdrc,bdmp,bdmv,bdsm]     #These are sources selected and then concated for variable, popPrices.
result=pd.concat(frame)
popPrices=result["Price"]

#Grand Mean
xpop=popPrices.mean()           #The mean

for popsq in popPrices:         #An attempt to have each individual sample treated with the grand mean. - success.
   ss=math.pow(popsq - xpop,2)  
   print(ss)                    #This will print floats individually, but need it in a list.

电流浮动输出：

244107.59945389628
54722.0922075194
6765577.961772737
643320.2371350557
...
...

通缉名单输出：

[244107.59945389628, 54722.0922075194, 6765577.961772737, 643320.2371350557, ..., ...]

使用列表理解

ss=[math.pow(popsq - xpop,2) for popsq in popPrices]

---

您需要将这些项目添加到列表中；现在您只是将它们赋给一个变量。试试这个：

resultList = []
for popsq in popPrices:treated with the grand mean. - success.
   resultList.append(math.pow(popsq - xpop,2))
print(resultList)
   

---

您可以创建一个空列表并附加结果

result=[]
for popsq in popPrices:          
   ss=math.pow(popsq - xpop,2)  
   result.append(ss)

result=[]
for popsq in popPrices:          
   ss=math.pow(popsq - xpop,2)  
   result.append(ss)