Python 迭代系列时出错

当我得到这个系列的第一个和第二个元素时，它工作正常，但是从元素3开始，当我尝试获取时会出现一个错误

type(X_test_raw)
Out[51]: pandas.core.series.Series

len(X_test_raw)
Out[52]: 1393

X_test_raw[0]
Out[45]: 'Go until jurong point, crazy.. Available only in bugis n great world la e buffet... Cine there got amore wat...'

X_test_raw[1]
Out[46]: 'Ok lar... Joking wif u oni...'

X_test_raw[2]

关键错误：2

---

没有值为

2

的索引

样本：

X_test_raw = pd.Series([4,8,9], index=[0,4,5])

print (X_test_raw)
0    4
4    8
5    9
dtype: int64

#print (X_test_raw[2])
#KeyError: 2

如果需要第三个值，请使用：

如果需要仅迭代值：

for x in X_test_raw:
    print (x)
4
8
9

如果需要

索引

和

值

使用：

---

考虑系列

X\u测试\u原始

X_test_raw = pd.Series(
    ['Go until jurong point, crazy.. Available only in bugis n great world la e buffet... Cine there got amore wat...',
     'Ok lar... Joking wif u oni...',
     'PLEASE DON\'T FAIL'
    ], [0, 1, 3])

X\u test\u raw

没有索引

2

，您正试图使用

X\u test\u raw[2]

引用该索引

改用

iloc

X_test_raw.iloc[2]

"PLEASE DON'T FAIL"

您可以使用

iteritems

for index_val, series_val in X_test_raw.iteritems():
    print series_val

Go until jurong point, crazy.. Available only in bugis n great world la e buffet... Cine there got amore wat...
Ok lar... Joking wif u oni...
PLEASE DON'T FAIL

---

有什么方法可以让我按顺序遍历这个系列吗？是的，我添加了解决方案。

X_test_raw.iloc[2]

"PLEASE DON'T FAIL"

for index_val, series_val in X_test_raw.iteritems():
    print series_val

Go until jurong point, crazy.. Available only in bugis n great world la e buffet... Cine there got amore wat...
Ok lar... Joking wif u oni...
PLEASE DON'T FAIL