随机排列Python OrderedDict的顺序

samplesDict是OrderedDict对象的默认Dict；从…起对于每个OrderedDict，我想创建一个随机排列顺序的副本

import collections
import copy
import random
...
randomizedSamplesDict = copy.deepcopy(samplesDict)
for k, i in samplesDict.iteritems():
  random.shuffle(i)

但我一直得到一个关键错误：随机56个；错误整数（例如56）每次都不同

为了举例说明，其中一个OrderedPicts可能是

OrderedDict([
  ('This is the first key', ['foo', 'baz']),
  ('And the second key', ['buz', 'baz']),
  ('Finally the third key', ['bar', 'foo'])])

我希望这本书能成为

OrderedDict([
  ('Finally the third key', ['bar', 'foo']),
  ('This is the first key', ['foo', 'baz']),
  ('And the second key', ['buz', 'baz'])])

---

我真的不知道你在这里想做什么；但有一种方法可以让你得到最终的结果：

ordered_dicts = samplesDict.values()

现在，如果要随机获取已排序的dict：

random.choice(ordered_dict)

the_dict_you_want = 1
random.choice([value for value in ordered_dicts[the_dict_you_want].values()])

如果要从其中一个有序DICT随机获取值：

random.choice(ordered_dict)

the_dict_you_want = 1
random.choice([value for value in ordered_dicts[the_dict_you_want].values()])

如果您只想从已排序的dict中随机排序项目，请将它们转换为普通dict；然后洗牌

import collections
import copy
import random

samplesDict = collections.OrderedDict()
samplesDict[1] = 10
samplesDict[2] = 20
samplesDict[3] = 30
print samplesDict

keys = samplesDict.keys()
random.shuffle(keys)
print keys

randomizedSamplesDict = collections.OrderedDict()
for k in keys :
    randomizedSamplesDict[k] = samplesDict[k]
print randomizedSamplesDict

输出：

OrderedDict([(1, 10), (2, 20), (3, 30)])
[2, 1, 3]
OrderedDict([(2, 20), (1, 10), (3, 30)])

正如你所看到的，第二个dict是由键洗牌的

使用您的数据，我得到了输出：

...
samplesDict = collections.OrderedDict([
  ('This is the first key', ['foo', 'baz']),
  ('And the second key', ['buz', 'baz']),
  ('Finally the third key', ['bar', 'foo'])])
...

OrderedDict([('This is the first key', ['foo', 'baz']), 
('And the second key', ['buz', 'baz']), 
('Finally the third key', ['bar', 'foo'])])

['And the second key', 'Finally the third key', 'This is the first key']

OrderedDict([('And the second key', ['buz', 'baz']), 
('Finally the third key', ['bar', 'foo']), 
('This is the first key', ['foo', 'baz'])])

---

您正在洗牌错误的项目，您应该在randomizedSamplesDict上迭代：

您已经制作了samplesDict的深度副本，因此如果要在randomizedSamplesDict中无序排列顺序，您需要迭代该dict，而不是原始dict

如果您确实想要一个随机顺序的带有SampleDictin中的键和值的新dict，请使用原始dict中的项在无序移动后创建一个新的OrderedDict：

import collections
import copy
import random
samplesDict = collections.OrderedDict([
  ('This is the first key', ['foo', 'baz']),
  ('And the second key', ['buz', 'baz']),
  ('Finally the third key', ['bar', 'foo'])])

items = list(samplesDict.items())
random.shuffle(items)
randomizedSamplesDict = collections.OrderedDict(copy.deepcopy(items))

---

要随机化有序数据，可以执行以下操作：

od = collections.OrderedDict([('This is the first key', ['foo', 'baz']), ('And the second key', ['buz', 'baz']),  ('Finally the third key', ['bar', 'foo'])])
items = od.items()
random.shuffle(items)
odrnd = collections.OrderedDict(items)
ornd
OrderedDict([('Finally the third key', ['bar', 'foo']), ('This is the first key', ['foo', 'baz']), ('And the second key', ['buz', 'baz'])])

---

在Python3.6+中，字典是有序的，因此以前使用过的解决方案可能会产生诸如TypeError之类的错误：“odict_items”对象不支持索引

相反，请尝试：

items = list(my_dict.items())
random.shuffle(items)
my_dict = OrderedDict(items)

---

什么是随机化的顺序？你的问题没有意义，除非你解释你试图用这个来完成什么。我得到了TypeError:“odict_items”对象不支持索引可能这是因为字典现在已经排序了？