PYTHON如何制作；关联数组"；

我制作了一个python脚本，需要在XML中包含一些参数。下面是XML：

<ROOT>
<FOLDERTYPES>
    <FOLDERTYPE_ID>
        <NAME>FOURNISSEUR</NAME>
        <ID>2</ID>
        <SUBFOLDER>
            <NAME>Administratif</NAME>
            <ID>4</ID>
        </SUBFOLDER>
        <SUBFOLDER>
            <NAME>Commandes</NAME>
            <ID>5</ID>
        </SUBFOLDER>
        <SUBFOLDER>
            <NAME>Factures</NAME>
            <ID>6</ID>
        </SUBFOLDER>
    </FOLDERTYPE_ID>
    <FOLDERTYPE_ID>
        <NAME>CLIENT</NAME>
        <ID>3</ID>
        <SUBFOLDER>
            <NAME>Administratif</NAME>
            <ID>4</ID>
        </SUBFOLDER>
        <SUBFOLDER>
            <NAME>Commandes</NAME>
            <ID>5</ID>
        </SUBFOLDER>
        <SUBFOLDER>
            <NAME>Factures</NAME>
            <ID>6</ID>
        </SUBFOLDER>
        <SUBFOLDER>
            <NAME>Logistique</NAME>
            <ID>7</ID>
        </SUBFOLDER>
    </FOLDERTYPE_ID>
</FOLDERTYPES>

但我需要所有的子文件夹，在这样的目录中：

{'FOURNISSEUR': {'id': '2', 'subfolders' : {'Administratif':'4','Commandes':'5','Factures':'6'}}, 'CLIENT': {'id': '3', 'subfolders' : {'Administratif':'4','Commandes':'5','Factures':'6','Logistique':'7'}}

以下是我目前拥有的一段代码：

def getFolderTypeArray(fileName):
    result = {}
    with open(fileName, 'rb') as config_file:
        content = config_file.read()
    config = BeautifulSoup(content, "lxml")

    folderTypesId = config.find_all('foldertype_id')
    for folderType in folderTypesId:
        label               = folderType.find('name').string
        folderTypeId        = folderType.find('id').string
        result[label]       = {'id' : folderTypeId}

加入另一个循环

folderTypesId = config.find_all('foldertype_id')
for folderType in folderTypesId:
    label               = folderType.find('name').string
    folderTypeId        = folderType.find('id').string
    subfolders = dict() 
    for s in folderType.find_all('subfolder'):
        subfolders[s.find('name').string] = s.find('id').string
    result[label]       = {'id' : folderTypeId, 'subfolders': subfolders}

---

它们在python中称为字典或dict，而不是关联数组。您可能需要一个xml解析器：那么，您在哪里生成子文件夹键？@cricket_007现在我没有为子文件夹编写任何代码。我只是做了一些尝试，但没有成功，因为我不知道如何实现这个检查：

result['subfolders']=some_dictionary

。在循环中构建内部字典。。。你已经在编字典了<代码>结果[标签]和

{'id'：folderTypeId}

folderTypesId = config.find_all('foldertype_id')
for folderType in folderTypesId:
    label               = folderType.find('name').string
    folderTypeId        = folderType.find('id').string
    subfolders = dict() 
    for s in folderType.find_all('subfolder'):
        subfolders[s.find('name').string] = s.find('id').string
    result[label]       = {'id' : folderTypeId, 'subfolders': subfolders}