Python 如何从数据帧创建列表列表

我有一个数据帧df，我想把数据帧转换成一个列表

    left_side                                  right_side                             similarity
0114600043776001 loan payment receipt         0421209017073500 loan payment receipt     0.689008
0114600043776001 loan payment receipt         0421209017073500 loan payment receipt     0.689008
vat onverve*issuance fee*506108               vat onverve*issuance fee*5061087       0.743522
vat onverve*issuance fee*506108               verve*issuance fee*506108*********1112    0.684342
verve*issuance fee*506108                     verve*issuance fee*506108*********8296    0.717817
verve*issuance fee*506108                     vat onverve*issuance fee*506108**         0.684342

maint fee recovery jun 2018                   vat maint fee recovery jun 2018          0.896607
maint fee recovery jun 2018                  vat maint fee recovery jun 2018         0.896607
maint fee recovery jun 2018                  vat maint fee recovery jun 2018         0.896607

预期输出应如下所示：

[[0114600043776001 loan payment receipt, 0421209017073500 loan payment receipt,
  0421209017073500 loan payment receipt],
[vat onverve*issuance fee*506108, vat onverve*issuance fee*5061087, 
  verve*issuance fee*506108*********1112], 
[verve*issuance fee*506108*********8296, verve*issuance fee*506108                    
 vat onverve*issuance fee*506108** ],...]

['0421209017073500 loan payment receipt0421209017073500 loan payment receipt0421209017073500 loan payment receipt0421209017073500 loan payment receipt0421209017073500 loan payment receipt0421209017073500 loan payment receipt']
['vat maint fee recovery jun 2018vat maint fee recovery jun 2018vat maint fee recovery jun 2018maint fee recovery jul 2018maint fee recovery oct 2018maint fee recovery jul 2018maint fee recovery jul 2018']

我曾尝试通过

左侧列对上述df进行分组，并将结果df转换为一个列表，但输出并非我所期望的。我需要你的帮助

groupp\u df=df.groupby（['left\u side']）。right\u side.sum（）。to\u frame（）

group\u df.values.tolist（）

输出如下所示：

[[0114600043776001 loan payment receipt, 0421209017073500 loan payment receipt,
  0421209017073500 loan payment receipt],
[vat onverve*issuance fee*506108, vat onverve*issuance fee*5061087, 
  verve*issuance fee*506108*********1112], 
[verve*issuance fee*506108*********8296, verve*issuance fee*506108                    
 vat onverve*issuance fee*506108** ],...]

['0421209017073500 loan payment receipt0421209017073500 loan payment receipt0421209017073500 loan payment receipt0421209017073500 loan payment receipt0421209017073500 loan payment receipt0421209017073500 loan payment receipt']
['vat maint fee recovery jun 2018vat maint fee recovery jun 2018vat maint fee recovery jun 2018maint fee recovery jul 2018maint fee recovery oct 2018maint fee recovery jul 2018maint fee recovery jul 2018']

我相信您正在寻找数据报上的
to_records（）
方法。
尝试
df.to_records（）
，您可以找到它的文档我相信您是在数据报上寻找
to_records（）
方法的。
请尝试
df.to_records（）
，您可以找到其文档您可以使用：

您可以使用：

看看这是否有帮助，看看这是否有帮助，我认为方法
to_records（）
从数据帧创建了一个与预期输出不同的元组列表。我认为方法
to_records（）
从与预期输出不同的数据帧创建了一个元组列表。