在Python中发送URL数据Curl/Json

我尝试在python中使用带有url参数的curl，但它返回“None”，在php中使用相同参数的相同api工作正常。 以下是我的python代码：

from StringIO import StringIO
import pycurl, json

apiurl = 'http://servername.com:7705'

data = json.dumps({"node": "test", "type": "get_by_field"})

c = pycurl.Curl()
c.setopt(pycurl.URL, apiurl)
c.setopt(pycurl.HTTPHEADER, ['Accept: application/json'])
c.setopt(pycurl.POST, 1)
c.setopt(pycurl.POSTFIELDS, data)
response = c.perform()
c.close()
print response

试试这个

import StringIO
import pycurl, json

fout = StringIO.StringIO()

apiurl = 'http://servername.com:7705'

data = json.dumps({"node": "test", "type": "get_by_field"})

c = pycurl.Curl()
c.setopt(pycurl.WRITEFUNCTION, fout.write)

c.setopt(pycurl.URL, apiurl)
c.setopt(pycurl.HTTPHEADER, ['Accept: application/json'])
c.setopt(pycurl.POST, 1)
c.setopt(pycurl.POSTFIELDS, data)
c.perform()
c.getinfo(pycurl.RESPONSE_CODE)
fout.getvalue()

试试这个

import StringIO
import pycurl, json

fout = StringIO.StringIO()

apiurl = 'http://servername.com:7705'

data = json.dumps({"node": "test", "type": "get_by_field"})

c = pycurl.Curl()
c.setopt(pycurl.WRITEFUNCTION, fout.write)

c.setopt(pycurl.URL, apiurl)
c.setopt(pycurl.HTTPHEADER, ['Accept: application/json'])
c.setopt(pycurl.POST, 1)
c.setopt(pycurl.POSTFIELDS, data)
c.perform()
c.getinfo(pycurl.RESPONSE_CODE)
fout.getvalue()

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我建议您研究一下

请求

哪个具有执行HTTP请求的良好API：我建议您研究一下

请求

哪个具有执行HTTP请求的良好API：