python中的扁平化索引

python中的扁平化索引,python,pandas,dataframe,Python,Pandas,Dataframe,我对python非常陌生,我一直在玩Panda数据帧,但是当我使用groupby时,我不再能够使用标签在数据帧上迭代 有人能帮我吗 newDF=df[df['Currency'].str.contains(currency)&df['Description'].str.contains('fx')] newDF=newDF.rename(index=str, columns={ "Paid": "Withdrawn"}) moneyWithdrawnByUserDF=pd.DataFr

我对python非常陌生,我一直在玩Panda数据帧,但是当我使用groupby时,我不再能够使用标签在数据帧上迭代

有人能帮我吗

newDF=df[df['Currency'].str.contains(currency)&df['Description'].str.contains('fx')]
newDF=newDF.rename(index=str, columns={ "Paid": "Withdrawn"})

moneyWithdrawnByUserDF=pd.DataFrame(newDF.groupby(['FirstName'])[['Withdrawn']].sum())

for index,row in moneyWithdrawnByUserDF.iterrows():
  print row['FirstName']
我得到的输出/错误如下:

Index([u'Email', u'FirstName', u'LastName', u'Owed', u'Withdrawn', u'UserId',

Traceback (most recent call last):

File "main.py", line 416, in <module>

sys.exit(main(sys.argv[1:]))

File "main.py", line 412, in main

parseGroups()

   u'Category', u'Description', u'Id', u'Currency', u'Cost', u'Details',

   u'GroupId'],

  dtype='object')

 File "main.py", line 45, in parseGroups

parseGroup(group) 

  File "main.py", line 81, in parseGroup processCurrencies(df)

  File "main.py", line 95, in processCurrencies processCurrency(df, currency)

  File "main.py", line 105, in processCurrency   moneyWithdrawnByUserDF=calculateMoneyWithdrawnByUser(df, currency)

 File "main.py", line 319, in calculateMoneyWithdrawnByUser

print row['FirstName']

 File "/usr/local/lib/python2.7/site-packages/pandas/core/series.py", line 601, in __getitem__

result = self.index.get_value(self, key)

 File "/usr/local/lib/python2.7/site-packages/pandas/core/indexes/base.py", line 2491, in get_value

  raise e1

 KeyError: 'FirstName'

谢谢你

我想你需要改变:

moneyWithdrawnByUserDF=pd.DataFrame(newDF.groupby(['FirstName'])[['Withdrawn']].sum())
作者:

对于数据帧,Or参数为_index=False:

moneyWithdrawnByUserDF= newDF.groupby(['FirstName'])['Withdrawn'].sum().reset_index()
moneyWithdrawnByUserDF= newDF.groupby(['FirstName'], as_index=False)['Withdrawn'].sum()