Python 如何将多个数字添加到多个列表中

Python 如何将多个数字添加到多个列表中,python,list,Python,List,我正在尝试将多个数字添加到多个列表中 我想将输入按以下顺序排列: 病人一:变量一,变量二,变量三 病人二:变量一,变量二,变量三 病人三:变量一,变量二,变量三 我已经想出了如何从字典中获取信息,但是顺序不对 但目前的输入顺序是: 患者一:变量一,患者二:变量一,患者三:变量一 患者一:变量二,患者二:变量二,患者三:变量二 患者一:变量三,患者二:变量三,患者三:变量三 有什么建议吗 while True: print("") number_of_persons

我正在尝试将多个数字添加到多个列表中

我想将输入按以下顺序排列: 病人一:变量一,变量二,变量三 病人二:变量一,变量二,变量三 病人三:变量一,变量二,变量三

我已经想出了如何从字典中获取信息,但是顺序不对

但目前的输入顺序是: 患者一:变量一,患者二:变量一,患者三:变量一 患者一:变量二,患者二:变量二,患者三:变量二 患者一:变量三,患者二:变量三,患者三:变量三

有什么建议吗

while True:
        print("")
        number_of_persons=(input("Please enter no. of persons \n"
         "Whole digit only. \n"
   "Positive Number:"))

        if number_of_persons.isdigit():
            print("Thanks")
            break
        try:
            pass
        except:
            pass

number_of_persons=int(number_of_persons)

variable_one = []
variable_two = []
variable_three = []

for person in range(0,number_of_persons):
    while True:
        print("Person Number: " ,person + 1)
        a=(input("     Enter variable one: "))

        if a.isdigit():
            print("Thanks")
            variable_one.append(a)
            break
        try:
            pass
        except:
            pass


for person in range(0,number_of_persons):
    while True:
        print("Person Number: " ,person + 1)
        b=(input("     Enter variable two: "))

        if b.isdigit():
            print("Thanks")
            variable_two.append(b)
            break
        try:
            pass
        except:
            pass


for person in range(0,number_of_persons):
    while True:
        print("Person Number: " ,person + 1)
        c=(input("     Enter variable Three: "))

        if c.isdigit():
            print("Thanks")
            variable_three.append(c)
            break
        try:
            pass
        except:
            pass        


print(variable_one)
print(variable_two)
print(variable_three)

首先,您处理的是列表,而不是字典。有一种方法是列出一系列列表:

while True:
        print("")
        number_of_persons=(input("Please enter no. of persons \n"
         "Whole digit only. \n"
   "Positive Number: "))

        if number_of_persons.isdigit():
            print("Thanks")
            break

number_of_persons=int(number_of_persons)

variables = []
for i in range(number_of_persons):
    variables.append([]) # a list of lists

for person in range(number_of_persons):
    for n in range(3):
        while True:
            a = input(f"Person Number: {person + 1}, variable {n + 1}: ")
            if a.isdigit():
                print("Thanks")
                variables[person].append(a)
                break

print(variables)

首先,您处理的是列表,而不是字典。有一种方法是列出一系列列表:

while True:
        print("")
        number_of_persons=(input("Please enter no. of persons \n"
         "Whole digit only. \n"
   "Positive Number: "))

        if number_of_persons.isdigit():
            print("Thanks")
            break

number_of_persons=int(number_of_persons)

variables = []
for i in range(number_of_persons):
    variables.append([]) # a list of lists

for person in range(number_of_persons):
    for n in range(3):
        while True:
            a = input(f"Person Number: {person + 1}, variable {n + 1}: ")
            if a.isdigit():
                print("Thanks")
                variables[person].append(a)
                break

print(variables)

这里有一种使用字典的方法。

def input_number(i):
    while True:
        try:
            number = int(input(f"\tEnter variable {i+1}: "))
            print("\n")
            break
        except ValueError:
            print("Only integers accepted!\n")
    return number


while True:
    try:
        print("Please enter no. of persons")
        print("Whole digit only.")
        number_of_persons = int(input("Positive number: "))
        break
    except ValueError:
        print("Only integers accepted!\n")


variables = {}
for person in range(number_of_persons):
    print("----------------------------------------")
    vars_ = []
    for i in range(number_of_persons):
        print(f"Person Number: {person + 1}")
        a = input_number(i)
        vars_.append(a)
    variables[person+1] = vars_


print("\n")
print(variables)
for j in range(len(variables)):
    print(variables[j+1])
样本输出:

Please enter no. of persons
Whole digit only.
Positive number: 2
----------------------------------------
Person Number: 1
    Enter variable 1: 50


Person Number: 1
    Enter variable 2: 100


----------------------------------------
Person Number: 2
    Enter variable 1: 150


Person Number: 2
    Enter variable 2: 200




{1: [50, 100], 2: [150, 200]}
[50, 100]
[150, 200]

这里有一种使用字典的方法。

def input_number(i):
    while True:
        try:
            number = int(input(f"\tEnter variable {i+1}: "))
            print("\n")
            break
        except ValueError:
            print("Only integers accepted!\n")
    return number


while True:
    try:
        print("Please enter no. of persons")
        print("Whole digit only.")
        number_of_persons = int(input("Positive number: "))
        break
    except ValueError:
        print("Only integers accepted!\n")


variables = {}
for person in range(number_of_persons):
    print("----------------------------------------")
    vars_ = []
    for i in range(number_of_persons):
        print(f"Person Number: {person + 1}")
        a = input_number(i)
        vars_.append(a)
    variables[person+1] = vars_


print("\n")
print(variables)
for j in range(len(variables)):
    print(variables[j+1])
样本输出:

Please enter no. of persons
Whole digit only.
Positive number: 2
----------------------------------------
Person Number: 1
    Enter variable 1: 50


Person Number: 1
    Enter variable 2: 100


----------------------------------------
Person Number: 2
    Enter variable 1: 150


Person Number: 2
    Enter variable 2: 200




{1: [50, 100], 2: [150, 200]}
[50, 100]
[150, 200]
“但是顺序不对”-我的意思是,你是这样编程的:你在迭代人,每个人都要求用户输入一种值,这样代码就可以按预期工作。如果你想为一个人请求多个值,可以这样迭代:
为范围内的人(…):为范围内的值(3):c=input(f“Enter variable{value\u number}:”)
“但是顺序错误”-我的意思是,你编程的方式是:对人进行迭代,每个人要求用户输入一种值,因此,代码按预期工作。如果您想为一个人请求多个值,请如下迭代:
为范围内的人(…):为范围内的值(3):c=input(f“输入变量{value\u number}:”)