Python 不'；t在第二次运行时存储输入的值

我做了一个石头、布、剪刀的游戏。 正如我所希望的，它工作得很好，但当第二次运行时，它不会存储输入的值，我如何修复它

请参阅下面的

while

循环，如果用户输入

y

，程序将再次运行

import random

tools =["Rock","Scissors","Paper"]
r = "".join(tools[0])
s = "".join(tools[1])
p = "".join(tools[-1])

def computer_predicion():
    computer_pred = random.choice(tools)
    return computer_pred

computer = computer_predicion()

def my_predicion():
    my_predicion = input("Choose (R)Rock,(S)Scissors,(P)Paper:")
    if my_predicion == "R" or my_predicion == "r":
        my_predicion = r
        return my_predicion
    elif my_predicion == "S" or my_predicion == "s":
        my_predicion = s
        return my_predicion
    elif my_predicion == "P" or my_predicion == "p":
        my_predicion = p
        return my_predicion
    else:
        print("Debils ir?")

human=my_predicion()

def game():
    message_win = ("You won!")
    message_lose = ("You lost!")
    message = "Computer:%s\nUser:%s"%(computer, human)
    if computer == r and human == r :
        print(message+"\nIt's draw")
    elif computer == p and human == p:
        print(message + "\nIt's draw")
    elif computer == s and human == s:
        print(message + "\nIt's draw")
    elif computer == r and human == p:
        print(message+'\n'+message_win)
    elif computer == p and human == r:
        print(message+'\n'+message_lose)
    elif computer == r and human == s:
        print(message+'\n'+message_lose)
    elif computer == s and human == r:
        print(message+'\n'+message_win)
    elif computer == p and human == s:
        print(message+'\n'+message_win)
    elif computer == s and human == p:
        print(message+'\n'+message_lose)
    else:
        pass

c = True
while c:      //Here code runs second time if user inputs Y or y.
    game()
    h = input("Continue?(Y/N):")
    if h == "Y" or h == "y":
        my_predicion()
        computer_predicion()
        pass
    elif h == "N" or h == "n":
        c = False
    else:
        print("Wrong symbol!")

---

该值未存储在第二个循环中，因为

computer = computer_predicion()
human = my_predicion()

在while循环外部显示

import random

tools =["Rock","Scissors","Paper"]
r="".join(tools[0])
s="".join(tools[1])
p="".join(tools[-1])
def computer_predicion():
    computer_pred = random.choice(tools)
    return computer_pred

def my_predicion():
    my_predicion = input("Choose (R)Rock,(S)Scissors,(P)Paper:")
    if my_predicion=="R" or my_predicion =="r":
       my_predicion = r
       return my_predicion
    elif my_predicion=="S" or my_predicion =="s":
       my_predicion = s
       return my_predicion
    elif my_predicion=="P" or my_predicion =="p":
       my_predicion = p
       return my_predicion
    else:
         print("Debils ir?")

def game():
    message_win = ("You won!")
    message_lose = ("You lost!")
    message = "Computer:%s\nUser:%s"%(computer,human)
    if computer ==r and human==r :
       print(message+"\nIt's draw")
    elif computer == p and human == p:
       print(message + "\nIt's draw")
    elif computer == s and human == s:
       print(message + "\nIt's draw")
    elif computer == r and human==p:
       print(message+'\n'+message_win)
    elif computer == p and human==r:
       print(message+'\n'+message_lose)
    elif computer == r and human==s:
       print(message+'\n'+message_lose)
    elif computer == s and human==r:
       print(message+'\n'+message_win)
    elif computer == p and human == s:
       print(message+'\n'+message_win)
    elif computer == s and human==p:
       print(message+'\n'+message_lose)
    else:
        pass

c=True
while c :      #Here code runs second time if user inputs Y or y.
  computer = computer_predicion()
  human = my_predicion()
  game()
  h = input("Continue?(Y/N):")
  if h=="Y" or h=="y":
     pass
  elif h=="N" or h=="n":
      c=False
  else:
       print("Wrong symbol!")

这是您的工作代码，我在while循环中迁移了双变量赋值

import random

tools =["Rock","Scissors","Paper"]
r="".join(tools[0])
s="".join(tools[1])
p="".join(tools[-1])
def computer_predicion():
    computer_pred = random.choice(tools)
    return computer_pred

def my_predicion():
    my_predicion = input("Choose (R)Rock,(S)Scissors,(P)Paper:")
    if my_predicion=="R" or my_predicion =="r":
       my_predicion = r
       return my_predicion
    elif my_predicion=="S" or my_predicion =="s":
       my_predicion = s
       return my_predicion
    elif my_predicion=="P" or my_predicion =="p":
       my_predicion = p
       return my_predicion
    else:
         print("Debils ir?")

def game():
    message_win = ("You won!")
    message_lose = ("You lost!")
    message = "Computer:%s\nUser:%s"%(computer,human)
    if computer ==r and human==r :
       print(message+"\nIt's draw")
    elif computer == p and human == p:
       print(message + "\nIt's draw")
    elif computer == s and human == s:
       print(message + "\nIt's draw")
    elif computer == r and human==p:
       print(message+'\n'+message_win)
    elif computer == p and human==r:
       print(message+'\n'+message_lose)
    elif computer == r and human==s:
       print(message+'\n'+message_lose)
    elif computer == s and human==r:
       print(message+'\n'+message_win)
    elif computer == p and human == s:
       print(message+'\n'+message_win)
    elif computer == s and human==p:
       print(message+'\n'+message_lose)
    else:
        pass

c=True
while c :      #Here code runs second time if user inputs Y or y.
  computer = computer_predicion()
  human = my_predicion()
  game()
  h = input("Continue?(Y/N):")
  if h=="Y" or h=="y":
     pass
  elif h=="N" or h=="n":
      c=False
  else:
       print("Wrong symbol!")

---

哇，虽然修理起来没那么容易。非常感谢。但有一个问题。当您运行此代码时，它会要求您输入两次值，所以若要修复此错误，您需要在用户选择继续后请求新值。@ivosorkins您已修复该问题吗？或者你还需要帮助吗？是的，我必须在函数中加入变量。