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python url模式中找不到url的反向_Python_Django - Fatal编程技术网
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python url模式中找不到url的反向

python django

python url模式中找不到url的反向,python,django,Python,Django,我做了URL配置 urlpatterns = [ path('', lambda request: redirect('stocks', permanent=False)), path('stocks', views.stocks.index, name='stocks.index'), path('stocks/<slug:slug>', views.stocks.show, name='stocks.show'), path('stocks/<slug:sl

我做了URL配置

urlpatterns = [
  path('', lambda request: redirect('stocks', permanent=False)),
  path('stocks', views.stocks.index, name='stocks.index'),
  path('stocks/<slug:slug>', views.stocks.show, name='stocks.show'),
  path('stocks/<slug:slug>/load', views.stocks.load, name='stocks.load')
]
当我尝试的时候，它给了我

但如果我尝试了，一切都可以

这里出了什么问题？

也许你应该使用
股票。指数
而不是
股票


path('', lambda request: redirect('stocks.index', permanent=False)),



是的，谢谢。我真蠢！我会删除问题不，所以最好不要删除有答案的问题

NoReverseMatch at /

Reverse for 'stocks' not found. 'stocks' is not a valid view function or pattern name.



path('', lambda request: redirect('stocks.index', permanent=False)),