Python 在一个范围内只使用一次函数的问题

我有一项任务，无法找出真正的解决办法

def triple(n):    #multiplies number with 3
    return (n*3)
def square(n):
    return (n**2)   #takes second power of number

for i in range(1,11):
    if triple(i) > square(i):
        print((f"triple({i})=={triple(i)} square({i})=={square(i)}"))

当值的平方大于值的三倍时，我应该停止迭代，而不在上一次迭代中打印任何内容

三重函数和平方函数每次迭代都必须调用一次

我试过的其他东西

    ls =[f"triple({i})=={triple(i)} square({i})=={square(i)}" for i in range(1,11) if triple(i) > square(i)]
    for i in ls:
        print(i)

---

有一个测试检查了我的答案，结果显示打印的行数错误，我问过课程中的某个人，他们刚刚告诉我，ı应该将从每个函数得到的值存储到一个变量中。这就是我试图做的，他们说的

根据你的评论，你的if条件全错了：

def triple(n):    #multiplies number with 3
    return (n*3)
def square(n):
    return (n**2)   #takes second power of number

for i in range(1,11):   #I asked to iterate 1 to 10
    triple_ = triple(i)
    square_ = square(i)
    if triple_ > square_:   #it should only print if the square of the number is smaller than the triple
        print(f"triple({i})=={triple(i)} square({i})=={square(i)}")

---

break将退出foor循环，您希望避免打印，这是一个完全不同的主题

请尝试以下代码

    def triple(n):    #multiplies number with 3
        return (n*3)
    def square(n):
        return (n**2)   #takes second power of number

    for i in range(1,11):   #I asked to iterate 1 to 10
        triple_ = triple(i)
        square_ = square(i)
        if triple_ < square_:   #it shouldnt print if square of the 
number is larger than the triple
            pass #it must END the loop
        else:
            print("Triple of " + str(i) + " is " + str(triple(i)) + " and its greater than or equal to its square " + str(square(i)))

---

在i=3的情况下，平方是9，三重也是9。如果你换成“是”，因为三元组3是9，平方组3是9，在这个条件下，你是在破坏。如果你想让程序继续，那么不要中断，简单。

    def triple(n):    #multiplies number with 3
        return (n*3)
    def square(n):
        return (n**2)   #takes second power of number

    for i in range(1,11):   #I asked to iterate 1 to 10
        triple_ = triple(i)
        square_ = square(i)
        if triple_ < square_:   #it shouldnt print if square of the 
number is larger than the triple
            pass #it must END the loop
        else:
            print("Triple of " + str(i) + " is " + str(triple(i)) + " and its greater than or equal to its square " + str(square(i)))