如何在python中打开.bashrc

在python中打开

.bashrc

文件时遇到问题。我编写了以下代码：

mydata = open ('/home/lpp/.bashrc', 'r')

with open('.bashrc', 'r') as content:
   fileContent = content.read()
   print(fileContent)

我明白了：

$ /usr/bin/python2.7 /home/lpp/lpp2016/Handin3.py
Process finished with exit code 0

with open('.bashrc', 'r') as content:
   fileContent = content.read()
   print(fileContent)

Python不会打开文件

.bashrc

。我做错了什么

fp = open(os.path.join((os.path.expanduser('~'), '.bashrc'))
fp.read()

with open('.bashrc', 'r') as content:
   fileContent = content.read()
   print(fileContent)

---

它正在打开并阅读所有内容

这是一个老问题。我也遇到了同样的问题，这是我阅读内容的解决方案

with open('.bashrc', 'r') as content:
   fileContent = content.read()
   print(fileContent)

---

您试图对

.bashrc

文件执行什么操作？它看起来是这样的（返回代码0，没有异常），但您对它不执行任何操作。

open（'~.bashrc'）