Python 如何从Django中的inlineadmin获取当前模型实例
我正在使用中给出的许多表单字段。 但在该函数中,我需要获取正在编辑的当前父对象Python 如何从Django中的inlineadmin获取当前模型实例,python,django,django-admin,Python,Django,Django Admin,我正在使用中给出的许多表单字段。 但在该函数中,我需要获取正在编辑的当前父对象 def formfield_for_manytomany(self, db_field, request, **kwargs): if db_field.name == "car": kwargs["queryset"] = Cars.objects.filter(owner=person) return super(myModel, self).formfield_for_manyt
def formfield_for_manytomany(self, db_field, request, **kwargs):
if db_field.name == "car":
kwargs["queryset"] = Cars.objects.filter(owner=person)
return super(myModel, self).formfield_for_manytomany(db_field, request, **kwargs)
如何获取正在编辑的人员?如果无法从
请求轻松获取人员
,您可能需要通过覆盖ModelAdmin.get\u form()
或InlineModelAdmin.get\u formset()
手动传递该人员:
或
为了访问InlineModelAdmin的父ModelAdmin的模型实例,我在过去使用过以下方法:
class PersonAdmin(ModelAdmin):
def get_formsets(self, request, obj=None, *args, **kwargs):
for inline in self.inline_instances:
inline._parent_instance = obj
yield inline.get_formset(request, obj)
class CarInline(TabularInline):
_parent_instance = None
def get_formset(self, *args, **kwargs):
def formfield_callback(field, **kwargs):
formfield = field.formfield(**kwargs)
if field.name == 'car':
formfield.queryset = Cars.objects.filter(owner=self._parent_instance)
return formfield
if self._parent_instance is not None:
kwargs['formfield_callback'] = formfield_callback
return super(CarInline, self).get_formset(*args,
**kwargs)
在get\u formset()
/get\u formset()
/formfield\u for\u dbfield()
中,我发现了一种更干净的方法,不需要所有的黑客攻击。使用Django的请求对象(您可以访问该对象)检索PK,然后从匹配中的参数中检索PK。例如:
from django.contrib import admin
from django.core.urlresolvers import resolve
from app.models import YourParentModel, YourInlineModel
class YourInlineModelInline(admin.StackedInline):
model = YourInlineModel
def get_parent_object_from_request(self, request):
"""
Returns the parent object from the request or None.
Note that this only works for Inlines, because the `parent_model`
is not available in the regular admin.ModelAdmin as an attribute.
"""
resolved = resolve(request.path_info)
if resolved.args:
return self.parent_model.objects.get(pk=resolved.args[0])
return None
def has_add_permission(self, request):
parent = self.get_parent_object_from_request(request)
if parent and parent.is_active is True:
return False
return super(YourInlineModelInline, self).has_add_permission(request)
def get_formset(self, request, *args, **kwargs):
"""
Using the get_formset example from above to override the QuerySet.
"""
def formfield_callback(field, **kwargs):
formfield = field.formfield(**kwargs)
if field.name == 'car':
formfield.queryset = self.parent_model.objects.filter(
owner=self.get_parent_object_from_request(request)
)
return formfield
if self.get_parent_object_from_request(request) is not None:
kwargs['formfield_callback'] = formfield_callback
return super(YourInlineModelInline, self).get_formset(*args, **kwargs)
@admin.register(YourParentModel)
class YourParentModelAdmin(admin.ModelAdmin):
inlines = [YourInlineModelInline]
我不明白。什么是formfield\u回调
什么是partial
回调是调用formfield\u for u manytomy
的幕后魔法,我们需要手动将obj
传递给它,以便从kwargs
内部formfield\u for u manytomy
中获取obj
。partial
部分生成了一个高阶函数,当被称为formfield\u回调(一些参数)
时,它的行为就像self.formfield\u for\u dbfield(请求,一些参数)
,您可以检查,一切都超出了我的理解。我有两个问题。从这里我可以得到更多关于formfield\u回调的信息。这是django的内部版本还是它的定制版本2。我如何知道kwargs中可用的东西、字段或函数。我想你怎么知道obj在里面kwargs@user20822261.formfield_回调在Django中有点硬编码,不传递obj
,但是我们可以很容易地定制它。2. kwargs
由Django表单填充以生成表单字段,因此它可能包含字段接受的可能内容:小部件
和查询集
。在这里,我们确实混合了具有不同目标的参数,因此请记住将其命名为唯一(obj
Here`)。我得到了这个错误\uuuu init\uuuuu(),得到了一个意外的关键字参数obj
,没有足够的时间进行适当的编辑,因此我将在这里留下一些注释,以便在Django 2.0下完成此工作:from Django.url import resolve
,pk=resolved.kwargs['object\u id']
,对于ModelAdminself.parent\u model
->self.model
我觉得这是更好、更简单的解决方案。我做了类似的操作,但没有使用resolve()函数。我只是做了一些类似于object\u id=request.path.split(“/”[4]
的事情,知道id永远是请求URL中的第四个参数。
class PersonAdmin(ModelAdmin):
def get_formsets(self, request, obj=None, *args, **kwargs):
for inline in self.inline_instances:
inline._parent_instance = obj
yield inline.get_formset(request, obj)
class CarInline(TabularInline):
_parent_instance = None
def get_formset(self, *args, **kwargs):
def formfield_callback(field, **kwargs):
formfield = field.formfield(**kwargs)
if field.name == 'car':
formfield.queryset = Cars.objects.filter(owner=self._parent_instance)
return formfield
if self._parent_instance is not None:
kwargs['formfield_callback'] = formfield_callback
return super(CarInline, self).get_formset(*args,
**kwargs)
from django.contrib import admin
from django.core.urlresolvers import resolve
from app.models import YourParentModel, YourInlineModel
class YourInlineModelInline(admin.StackedInline):
model = YourInlineModel
def get_parent_object_from_request(self, request):
"""
Returns the parent object from the request or None.
Note that this only works for Inlines, because the `parent_model`
is not available in the regular admin.ModelAdmin as an attribute.
"""
resolved = resolve(request.path_info)
if resolved.args:
return self.parent_model.objects.get(pk=resolved.args[0])
return None
def has_add_permission(self, request):
parent = self.get_parent_object_from_request(request)
if parent and parent.is_active is True:
return False
return super(YourInlineModelInline, self).has_add_permission(request)
def get_formset(self, request, *args, **kwargs):
"""
Using the get_formset example from above to override the QuerySet.
"""
def formfield_callback(field, **kwargs):
formfield = field.formfield(**kwargs)
if field.name == 'car':
formfield.queryset = self.parent_model.objects.filter(
owner=self.get_parent_object_from_request(request)
)
return formfield
if self.get_parent_object_from_request(request) is not None:
kwargs['formfield_callback'] = formfield_callback
return super(YourInlineModelInline, self).get_formset(*args, **kwargs)
@admin.register(YourParentModel)
class YourParentModelAdmin(admin.ModelAdmin):
inlines = [YourInlineModelInline]