Python 读入行间数组

有没有一种方法可以使用某些模式作为“屏障”将文件的一部分读取到数组中

编辑：经过一点搜索和混乱，我已经管理了[INTERNAMITE]和[depotNum]之间的行

但在打印时，它的作用如下：

# intermediate dir (output dir of route chopper), is route files and

#   common files for each truck ready for customer format processing



PX12RUJ = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUJ/

PX12RUR = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUR/

PX12RUV = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUV/

#PX12RUU = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUU/

PX12WLJ = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12WLJ/

#PX12WLL = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12WLL/

PX12WLK = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12WLK/

PX12RUW = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUW/

WN14YGV = /shares/MILKLINK/PPdir/lloydF/tempFiles/WN14YGV/

WN14YGY = /shares/MILKLINK/PPdir/lloydF/tempFiles/WN14YGY/







# --------------------

这是我的代码，我试图去除任何以#或空白/空白开头的行，但出于某种原因，它不会删除多余的行

#!/usr/bin/python

FILE=open("/shares/MILKLINK/PPdir/lloydF/conDalt.ini" , 'r')
for LINE in FILE:
    LINE = filter(None,LINE)
    LINE = filter(lambda x: not x.startswith('#'), LINE)
    if LINE.strip() == '[intermediate]':
        break
for LINE in FILE:
    if LINE.strip() == '[depotNum]':
        break
    print LINE        

你可以试试这种东西

我会用：

import re
lines_list = []
with open(path,'r') as file:
    for line in file.readlines()
        if bool(re.match(you_regex, line)):
            lines_list.append(line)

---

那么您自己尝试了什么呢？答案部分取决于文件中的行是否已排序且唯一（您发布的内容未排序）。@RvdK添加了代码和输出数据，对延迟表示歉意我尝试了您的解决方案，但唯一返回的是[]这是我的regex

打印re.findall（\[intermediate\].+（？=\[deptnum\]）”，FILE.read（））“

有什么想法我哪里出错了吗？

import re
f=open("file.txt",'r')
print re.findall(r""+start_pattern+"[\s\S]+?"+end_pattern",f.read())

import re
lines_list = []
with open(path,'r') as file:
    for line in file.readlines()
        if bool(re.match(you_regex, line)):
            lines_list.append(line)