Python 巨蟒石剪刀错误

我在尝试运行此程序时遇到了一个错误，即没有定义x。我是python新手。任何帮助都将不胜感激。另外，任何让这段代码更干净的方法都会很好

---

变量

playachoice

是函数

playainput（）

的本地变量。因此在

playanput（）的末尾添加：

return playerinput

然后将x赋值更改为：

x = playainput()

更新：

您有几个小错误，让我们试试：

import random

choices = ["rock", 'paper', 'scissors']

def playainput():
    while True:
        playerinput = input("Input rock, paper, or scissors:  ")
        if playerinput in choices:
            print("You chose", playerinput)
            break

        print ("oops type again")
    return playerinput

def choose(x):
    choice = random.choice(x)
    print ("I chose %s" % choice)
    return choice

x = playainput()
y = choose(choices)

outcomes = {
    ("rock", "rock"): "tie!",
    ("rock", "paper"): "you lose",
    ("rock", "scissors"): "you win",
    ("paper", "rock"): "you win",
    ("paper", "paper"): "tie!",
    ("paper", "scissors"): "you lose",
    ("scissors", "rock"): "you lose",
    ("scissors", "paper"): "you win",
    ("scissors", "scissors"): "tie!",
}
print(outcomes[x, y])

首先，变量
playachoice
是本地变量，而不是全局变量，这意味着您只能从
playanput（）中访问。因此，您必须先从
playanput（）
返回变量，然后才能分配
x=playanput（）

第二，为什么您试图将
playachoice
分配给x？该变量将包含
“您选择了摇滚”
等等。我认为您需要返回
playerinput
，以便在下面进行比较。因此，在
playanput（）的末尾添加
print playachoice
和
return playerinput

第三，不必将
playachoice
初始化为空字符串，然后在if-else子句中添加以下字符串。我认为你应该可以直接将“你选择了摇滚乐”等分配给playachoice

第四，使用
raw\u input（）
而不是
input（）
<代码>输入（）

第五，您还应该从
choose（x）

我认为这应该行得通

import random

choices = ["rock", 'paper', 'scissors']


def playainput():

    playerinput = raw_input("Input rock, paper, or scissors:  ")

    if playerinput == ("rock"):
                playachoice = ("you chose rock")
    elif playerinput == ("paper"):
                playachoice = ("you chose paper")
    elif playerinput == ("scissors"):
                playachoice = ("You chose scissors")
    else:
        print ("oops type again")
        playainput()

    return playerinput



def choose(x):
    choice = random.choice(x)
    print ("I chose %s" %choice)
    return choice

x = playainput()
y = choose(choices)

if x == ("rock") and y == ("scissors"):
    print ("you win")
if x == ("rock") and y == ("paper"):
    print ("you lose!")
if x == ("rock") and y == ("rock"):
    print ("tie")

if x == ("paper") and y == ("scissors"):
    print ("I win!")
if x == ("paper") and y == ("paper"):
    print ("tie!")
if x == ("paper") and y == ("rock"):
    print ("you win!")

if x == ("scissors") and y == ("scissors"):
    print ("tie!")
if x == ("scissors") and y == ("paper"):
    print ("you win!")
if x == ("scissors") and y == ("rock"):
    print ("you lose!")

请在您的答案中直接包含完整的回溯、逐字记录。谢谢。旁注：所有围绕
str
literals的随机参数都是毫无意义的，只会让代码更加混乱（它们对行为没有任何影响）。你为什么认为你需要它们？这很有效！谢谢你帮了一个python新手。
import random

choices = ["rock", 'paper', 'scissors']


def playainput():

    playerinput = raw_input("Input rock, paper, or scissors:  ")

    if playerinput == ("rock"):
                playachoice = ("you chose rock")
    elif playerinput == ("paper"):
                playachoice = ("you chose paper")
    elif playerinput == ("scissors"):
                playachoice = ("You chose scissors")
    else:
        print ("oops type again")
        playainput()

    return playerinput



def choose(x):
    choice = random.choice(x)
    print ("I chose %s" %choice)
    return choice

x = playainput()
y = choose(choices)

if x == ("rock") and y == ("scissors"):
    print ("you win")
if x == ("rock") and y == ("paper"):
    print ("you lose!")
if x == ("rock") and y == ("rock"):
    print ("tie")

if x == ("paper") and y == ("scissors"):
    print ("I win!")
if x == ("paper") and y == ("paper"):
    print ("tie!")
if x == ("paper") and y == ("rock"):
    print ("you win!")

if x == ("scissors") and y == ("scissors"):
    print ("tie!")
if x == ("scissors") and y == ("paper"):
    print ("you win!")
if x == ("scissors") and y == ("rock"):
    print ("you lose!")