Python beautifulSoup只显示最后一个结果

我目前正在尝试学习python网页抓取。我做的每件事都和教程中的一模一样。但是循环不起作用。如果我用print测试它，它只显示最后一个条目

import requests
from bs4 import BeautifulSoup as soup
import lxml

url = "https://www.moviepilot.de/dvd/dvds-neu"

agent = {"User-Agent":'Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/59.0.3071.115 Safari/537.36'}

page = requests.get(url, headers=agent)

page_soup = soup(page.content, "html.parser")

ergebnisse = page_soup.findAll("li", {"class":"movie"})

for container in ergebnisse:
    filmname = container.a["title"]



print(filmname)

---

每次循环时，都会覆盖filmname的值，因此它可能只打印最后一个值。您需要从循环内部将每个电影名添加到空列表中

试试这个：

import requests
from bs4 import BeautifulSoup as soup
import lxml

url = "https://www.moviepilot.de/dvd/dvds-neu"

agent = {"User-Agent":'Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/59.0.3071.115 Safari/537.36'}

page = requests.get(url, headers=agent)

page_soup = soup(page.content, "html.parser")

ergebnisse = page_soup.findAll("li", {"class":"movie"})
films = []
for container in ergebnisse:
    filmname = container.a["title"]
    films.append(filmname)



print(films)

---

目前，您的

for

循环正在重新分配

filmname

，因此，只会存储上一次迭代的值。但是，您可以使用列表理解来存储所有必要的值：

ergebnisse = page_soup.findAll("li", {"class":"movie"})
names = [container.a["title"] for container in ergebnisse]

---

您也可以使用选择器执行相同的操作：

import requests
from bs4 import BeautifulSoup as soup

URL = "https://www.moviepilot.de/dvd/dvds-neu"

page = requests.get(URL, headers={"User-Agent":"Mozilla/5.0"})

page_soup = soup(page.content, "html.parser")

container = '\n'.join([item["title"] for item in page_soup.select("li.movie a")])
print(container)