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Python 我可以使用参数引用变量吗?_Python_Python 3.x - Fatal编程技术网

Python 我可以使用参数引用变量吗?

Python 我可以使用参数引用变量吗?,python,python-3.x,Python,Python 3.x,我可以使用上面声明的函数的参数引用特定变量吗?简短回答,否。使用字典 def rock_paper_scissors_lizard_spock(player1, player2): # each variable stores what it can defeat scissors = ['paper','lizard'] rock = ['lizard', 'scissors'] paper = ['rock','spock'] lizard = ['

我可以使用上面声明的函数的参数引用特定变量吗?

简短回答,否。使用字典

def rock_paper_scissors_lizard_spock(player1, player2):

    # each variable stores what it can defeat
    scissors = ['paper','lizard']
    rock = ['lizard', 'scissors']
    paper = ['rock','spock']
    lizard = ['spock','paper']
    spock = ['scissors','rock']


    if str(player2) in player1:
        print('player 1 wins')


rock_paper_scissors_lizard_spock('rock','spock')

简短回答,不。使用字典

def rock_paper_scissors_lizard_spock(player1, player2):

    # each variable stores what it can defeat
    scissors = ['paper','lizard']
    rock = ['lizard', 'scissors']
    paper = ['rock','spock']
    lizard = ['spock','paper']
    spock = ['scissors','rock']


    if str(player2) in player1:
        print('player 1 wins')


rock_paper_scissors_lizard_spock('rock','spock')

这可能吗?有什么建议吗?我是个新手,你可以用一张单子。那么
d['rock']=['lizard','剪刀]
@MichaelRisling,下面的答案有用吗?如果是这样,请随意接受答案(勾选左侧),以便其他用户可以看到经过测试的答案。这可能吗?有什么建议吗?我是个新手,你可以用一张单子。那么
d['rock']=['lizard','剪刀]
@MichaelRisling,下面的答案有用吗?如果是这样,请随意接受答案(勾选左侧),以便其他用户可以看到经过测试的答案。