Python SymPy：如何使'nsolve'返回包含找到的解决方案的词典

我想使用

solve

作为

solve

的回退，并喜欢使用

dict=True

使

solve

返回一个包含找到的解决方案和相应变量的字典。但是，

nsolve

似乎没有此选项

这就是我正在使用的解决方法：

from sympy import *

def nsolve(equations, variables, guesses, **flags):
    from sympy import nsolve as originalnsolve
    result = originalnsolve(equations, variables, guesses, **flags)
    if "dict" in flags and flags["dict"]:
        return [dict(zip(variables, [float(value) for value in result]))]
    else:
        return result

x, y = symbols("x y")
equations = [Eq(2*x+y, 3), Eq(y-x, 1)]
variables = [x, y]
guesses = [1, 1]

print("solve with dict = True produces:\n%s\n" % solve(equations, variables, dict = True) + "The result is a dictionary, as needed\n")
print("nsolve without dict = True produces:\n%s\n" % nsolve(equations, variables, guesses) + "nsolve doesn't return a dictionary\n")
print("nsolve with dict = True produces:\n%s\n" % nsolve(equations, variables, guesses, dict = True) + "My workaround wrapper function returns a dictionary\n")

solve with dict = True produces:
[{x: 2/3, y: 5/3}]
The result is a dictionary, as needed

nsolve without dict = True produces:
[0.666666666666667]
[ 1.66666666666667]
nsolve doesn't return a dictionary

nsolve with dict = True produces:
[{x: 0.6666666666666666, y: 1.6666666666666667}]
My workaround wrapper function returns a dictionary

输出为：

from sympy import *

def nsolve(equations, variables, guesses, **flags):
    from sympy import nsolve as originalnsolve
    result = originalnsolve(equations, variables, guesses, **flags)
    if "dict" in flags and flags["dict"]:
        return [dict(zip(variables, [float(value) for value in result]))]
    else:
        return result

x, y = symbols("x y")
equations = [Eq(2*x+y, 3), Eq(y-x, 1)]
variables = [x, y]
guesses = [1, 1]

print("solve with dict = True produces:\n%s\n" % solve(equations, variables, dict = True) + "The result is a dictionary, as needed\n")
print("nsolve without dict = True produces:\n%s\n" % nsolve(equations, variables, guesses) + "nsolve doesn't return a dictionary\n")
print("nsolve with dict = True produces:\n%s\n" % nsolve(equations, variables, guesses, dict = True) + "My workaround wrapper function returns a dictionary\n")

solve with dict = True produces:
[{x: 2/3, y: 5/3}]
The result is a dictionary, as needed

nsolve without dict = True produces:
[0.666666666666667]
[ 1.66666666666667]
nsolve doesn't return a dictionary

nsolve with dict = True produces:
[{x: 0.6666666666666666, y: 1.6666666666666667}]
My workaround wrapper function returns a dictionary

我的问题：

from sympy import *

def nsolve(equations, variables, guesses, **flags):
    from sympy import nsolve as originalnsolve
    result = originalnsolve(equations, variables, guesses, **flags)
    if "dict" in flags and flags["dict"]:
        return [dict(zip(variables, [float(value) for value in result]))]
    else:
        return result

x, y = symbols("x y")
equations = [Eq(2*x+y, 3), Eq(y-x, 1)]
variables = [x, y]
guesses = [1, 1]

print("solve with dict = True produces:\n%s\n" % solve(equations, variables, dict = True) + "The result is a dictionary, as needed\n")
print("nsolve without dict = True produces:\n%s\n" % nsolve(equations, variables, guesses) + "nsolve doesn't return a dictionary\n")
print("nsolve with dict = True produces:\n%s\n" % nsolve(equations, variables, guesses, dict = True) + "My workaround wrapper function returns a dictionary\n")

solve with dict = True produces:
[{x: 2/3, y: 5/3}]
The result is a dictionary, as needed

nsolve without dict = True produces:
[0.666666666666667]
[ 1.66666666666667]
nsolve doesn't return a dictionary

nsolve with dict = True produces:
[{x: 0.6666666666666666, y: 1.6666666666666667}]
My workaround wrapper function returns a dictionary

• 我是否缺少一个更简单的方法来让

  nsolve

  返回字典

• 如果不是：我的方法有问题吗

---

nsolve

没有

dict

选项。如果您想要请求一个，您应该在中打开一个功能请求，或者打开一个实现它的请求

好的，谢谢你的回复。那我就试试吧